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romanna [79]
3 years ago
10

A boy who exerts a 300-N force on the ice of a skating rink is pulled by his friend with a force of 75 N, causing the boy to acc

elerate across the ice. If drag and the friction from the ice apply a force of 5 N on the boy, what is the magnitude of the net force acting on him?
Physics
1 answer:
Bezzdna [24]3 years ago
7 0

Answer:

70 N

Explanation:

Draw a free body diagram of the boy.  There are four forces:

Weight force mg pulling down,

A 300 N normal force pushing up,

A 75 N applied force pulling right,

and a 5 N friction force pushing left.

The boy's acceleration in the y direction is 0, so the net force in the y direction is 0.

The net force in the x direction is 75 N − 5 N = 70 N.

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I believe its vibration or my teacher taught me wrong

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What is produced when constantly changing electric and magnetic fields cause electrically charged particles to vibrate or accele
zhannawk [14.2K]
It would be D) Electromagnetic waves
Hope it helped!
4 0
3 years ago
Urippe Went to start his lawnmower and was having trouble. At the same moment, Uwi was starting her identical lawnmower in the y
Ivan

Answer:

As each mower presumably needs the same torque to start, and torque is a product of force and moment arm, the longer moment arm of 10.42 cm on Uwi's mower means lower force is required when compared to Urippe's shorter moment arm of 1.35 cm

350 rev/min = 350(2π) / 60 = 36.652 rad/s

36.652 rad/s / 0.294 s = 124.66... <u>125 rad/s²</u>

a = αR = 125(0.1042) = 12.990... <u>13 m/s²</u>

a =  αR = 125(0.0135) = 1.68299... <u>1.7 m/s²</u>

I am GUESSING that we are supposed to model these mowers as a uniform disk

  τ = Iα

FR = (½mr²)α

  F = mr²α/2R

Urippe's pull  = (3.56)(0.2041²)(124.66) / (2(0.0135)) = 702.008... <u>702 N</u>

Usi's pull =        (3.56)(0.2041²)(124.66) / (2(0.1042)) = 90.9511...<u>91.0 N</u>

L = Iω = (½(3.56)(0.2041²))36.652 = 2.71771...<u>2.72 kg•m²/s  down</u>

using the right hand rule

8 0
3 years ago
An interference pattern is produced by light with a wavelength 550 nm from a distant source incident on two identical parallel s
ad-work [718]

Answer:

a

 \theta  =  0.0022 rad

b

 I  =  0.000304 I_o

Explanation:

From the question we are told that  

   The  wavelength of the light is \lambda  = 550 \ nm  =  550 *10^{-9} \ m

    The  distance of the slit separation is  d = 0.500 \ mm = 5.0 *10^{-4} \ m

 

Generally the condition for two slit interference  is  

     dsin \theta =  m \lambda

Where m is the order which is given from the question as  m = 2

=>    \theta  =  sin ^{-1} [\frac{m \lambda}{d} ]

 substituting values  

      \theta  =  0.0022 rad

Now on the second question  

   The distance of separation of the slit is  

       d =  0.300 \ mm  =  3.0 *10^{-4} \ m

The  intensity at the  the angular position in part "a" is mathematically evaluated as

      I  =  I_o  [\frac{sin \beta}{\beta} ]^2

Where  \beta is mathematically evaluated as

       \beta  =  \frac{\pi *  d  *  sin(\theta )}{\lambda }

  substituting values

     \beta  =  \frac{3.142  *  3*10^{-4}  *  sin(0.0022 )}{550 *10^{-9} }

    \beta  = 0.06581

So the intensity is  

    I  =  I_o  [\frac{sin (0.06581)}{0.06581} ]^2

   I  =  0.000304 I_o

3 0
3 years ago
An electric current in a wire flows to the West in a magnetic field directed
vredina [299]

Answer: Current in a wire

We can use the same right-hand rule as we did for the moving charges—pointer finger in the direction the current is flowing, middle finger in the direction of the magnetic field, and thumb in the direction the wire is pushed.

Explanation:

7 0
3 years ago
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