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zysi [14]
4 years ago
9

I NEED HELP PLEASE, THANKS! :)

Physics
1 answer:
Rainbow [258]4 years ago
4 0

Explanation:

Usually when we think of waves, we think of transverse waves.  These are waves where points move up and down perpendicular to the motion of the wave.  Examples include water waves, whipping a rope, or even doing the "wave" in a crowd.  You can think of these as "two dimensional" waves.

Longitudinal waves are waves where points move left or right, parallel to the motion of the wave.  In other words, there is compression and expansion of the medium.  Examples include sound waves, or pulses in a slinky.

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Food chains are made up of many_____________. HELP ASAP!!!!!
Mashcka [7]
Hello!

Possible answer could be Organisms

There are a lot of Organisms in the overall food chain.

Hope this helped!
4 0
3 years ago
Read 2 more answers
A high ____will have a short wavelength.​
Sphinxa [80]

Question:

A high ____will have a short wavelength

Answer:

That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength. Light waves have very, very short wavelengths

Explanation:

Hope it help

4 0
3 years ago
Read 2 more answers
Swinging a golf club or baseball bat are examples of ______________ stretching.
kari74 [83]

Answer:

Static stretching is the answer.

Explanation:

Static stretching is the most common form that greatly improves flexibility. However, static stretches does little to contract the muscles needed to generate powerful golf swings. Dynamic stretches help improve your range of motion while reducing muscle stiffness.

6 0
4 years ago
At noon on a clear day, sunlight reaches the earth\'s surface at Madison, Wisconsin, with an average power of approximately 3.00
alexira [117]
Energy of a wave:
E = nhc/λ
3000 = (n x 6.63 x 10⁻³⁴ x 3 x 10⁸)/(510 x 10⁻⁹)
n = 7.69 x 10 ²¹ photons per second per meter²
2.70 cm² = 2.70/10,000 m²
= 2.7 x 10⁻⁴
Photons per second = 7.69 x 10 ²¹ x 2.7 x 10⁻⁴
= 2.08 x 10¹⁸ photons per second
4 0
3 years ago
Determine the stopping distances for a car with an initial speed of 88 km/h and human reaction time of 2.0 s for the following a
seropon [69]

Explanation:

Given that,

Initial speed of the car, u = 88 km/h = 24.44 m/s

Reaction time, t = 2 s

Distance covered during this time, d=24.44\times 2=48.88\ m

(a) Acceleration, a=-4\ m/s^2

We need to find the stopping distance, v = 0. It can be calculated using the third equation of motion as :

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{-(24.44)^2}{2\times -4}

s = 74.66 meters

s = 74.66 + 48.88 = 123.54 meters

(b) Acceleration, a=-8\ m/s^2

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{-(24.44)^2}{2\times -8}

s = 37.33 meters

s = 37.33 + 48.88 = 86.21 meters

Hence, this is the required solution.

4 0
3 years ago
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