Acceleration =change in velocity/change in time.
So final speed minus initial velocity/time
3.1-v/2=a
The wavelength would decrease because frequency is inversly proportional to the wavelength provided the speed is constant: f=v/λ
Answer:
The speed of the stone just before it hits the ground is 18.54 m/s
Explanation:
Given that,
Initial speed of the stone, u = 8 m/s
The stone is thrown downward from a height of 14 m
We need to find the speed of the stone just before it hits the ground. It can be calculated using third equation of motion as :

v is the speed of the stone just before it hits the ground


v = 18.54 m/s
So, the speed of the stone just before it hits the ground is 18.54 m/s. Hence, this is the required solution.
Answer:
Jupiter's gravitational acceleration is 24.8 m/s^2
Explanation:
Recall that the weight under the influence of a gravitational acceleration G is defined as:
Weight = m * G
Then, in our case we have
372 N = 15 kg * G
G = 372/15 m/s^2
G = 24.8 m/s^2