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Rus_ich [418]
3 years ago
9

The 700th term in a geometric sequence is 20. If the common ratio of the sequence is 0.25, what is the 699th term?

Mathematics
2 answers:
GenaCL600 [577]3 years ago
6 0
There are two ways to solve this problem. First, you can use the derived formula for geometric sequence which can be used to find any nth term of the sequence. Or, we can use the second easier way. Since we are given with the 700th term, and the asked is the 699th term, then that means,

(699th term)*(Common Ratio) = 700th term
699th term = 700th term/Common Ratio = 20/0.25 = <em>80</em>
Jlenok [28]3 years ago
6 0

Answer:

80

Step-by-step explanation:

(699th term)*(Common Ratio) = 700th term

699th term = 700th term/Common Ratio = 20/0.25 = 80

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Find the root(s) of f (x) = (x + 5)3(x - 9)2(x + 1). -5 with multiplicity 3 5 with multiplicity 3 -9
faust18 [17]

Answer:

  -5, multiplicity 3; +9, multiplicity 2; -1

Step-by-step explanation:

The roots of f(x) are those values of x that make the factors be zero. For a factor of x-a, the root is x=a, because a-a=0. If the factor appears n times, then the root has multiplicity n.

f(x) = (x+5)^3(x-9)^2(x+1) has roots ...

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4 0
3 years ago
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jolli1 [7]

Answer:

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4 0
3 years ago
Why couldn't you use synthetic division for the following problern? Make sure to explain fully.
yawa3891 [41]
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5 0
3 years ago
Pamela drove her car 99 kilometers and used 9 liters of fuel. She wants to know how many kilometers (k) she can drive with 12 li
masya89 [10]

Answer:

132 kilometers

Step-by-step explanation:

Given: Pamela drove her car 99 kilometers and used 9 liters of fuel.

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7 0
3 years ago
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4 0
3 years ago
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