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Rus_ich [418]
3 years ago
9

The 700th term in a geometric sequence is 20. If the common ratio of the sequence is 0.25, what is the 699th term?

Mathematics
2 answers:
GenaCL600 [577]3 years ago
6 0
There are two ways to solve this problem. First, you can use the derived formula for geometric sequence which can be used to find any nth term of the sequence. Or, we can use the second easier way. Since we are given with the 700th term, and the asked is the 699th term, then that means,

(699th term)*(Common Ratio) = 700th term
699th term = 700th term/Common Ratio = 20/0.25 = <em>80</em>
Jlenok [28]3 years ago
6 0

Answer:

80

Step-by-step explanation:

(699th term)*(Common Ratio) = 700th term

699th term = 700th term/Common Ratio = 20/0.25 = 80

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Answer:

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Step-by-step explanation:

Given the function

f\left(x\right)=-\frac{14}{x^2}

at x₁ = 1,

f(x₁) = f(1) =  -14/(1)² = -14/1 = -14

at x₂ = 2,

f(x₂) = f(2) = -14/(2)² = -14/(4) = -3.5

Using the formula to determine the average rate of change at which the total cost increases will be:

Average rate of change = [f(x₂) - f(x₁)] / [ x₂ - x₁]

                                        = [-3.5 - (-14)] / [2 - 1]

                                        = [-3.5 + 14] / [1]

                                        = 10.5 / 1

                                        = 10.5

Therefore, the average rate of change of the function from x=1 to x=2 will be: 10.5                      

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