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Rus_ich [418]
3 years ago
9

The 700th term in a geometric sequence is 20. If the common ratio of the sequence is 0.25, what is the 699th term?

Mathematics
2 answers:
GenaCL600 [577]3 years ago
6 0
There are two ways to solve this problem. First, you can use the derived formula for geometric sequence which can be used to find any nth term of the sequence. Or, we can use the second easier way. Since we are given with the 700th term, and the asked is the 699th term, then that means,

(699th term)*(Common Ratio) = 700th term
699th term = 700th term/Common Ratio = 20/0.25 = <em>80</em>
Jlenok [28]3 years ago
6 0

Answer:

80

Step-by-step explanation:

(699th term)*(Common Ratio) = 700th term

699th term = 700th term/Common Ratio = 20/0.25 = 80

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Cristal's gross semimonthly salary is $2968.50. What is the maximum amount she can afford to borrow for a home mortgage?
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Answer:

C) 142,488

Step-by-step explanation: by adding up here semimonthly, also took test.

8 0
3 years ago
Convert (CAB) 16 to decimal<br><br>need help asap
Mrrafil [7]

Remark

So CAB is a base 16 number? I hope that's correct. I'll treat it that way. If I am incorrect, please leave a note and I'll modify my answer accordingly.

Expand

A = 10 in decimal

B = 11  in decimal

C = 12 in decimal

B is the "units" value in decimal it is 11

A is the "tens" value or 12 place and in decimal you would get 12 * 10 = 120

C is the "hundreds" value or 12^2 place and in decimal you would get 144*12 =1728

Now you need to all all three results together. 11 + 120 + 1728 = 1850

Answer

(CAB)_16 = 1850 in decimal

6 0
3 years ago
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Imagine we are throwing a five-sided die 50 times. On average, out of these 50 throws, how many times would this five-sided die
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16.6 times because if there is 3 numbers you simply divide it into 50
4 0
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Solve for the missing side length, rounded to the nearest tenth.
zaharov [31]

Answer: 5.2 mm 7 mm About mm

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6 0
3 years ago
Please!!! Help!!! Brainliest of Right! it goes as 50 point in the end but i used 100 point if you help me i will help you!!
vekshin1

Answer:

2.  3.913 kg (3 dp)

3.  light cream

4.  240 CoffeeStops

5.  7 CoffeeStops per square mile

6.  2,861 cups of coffee each day

Step-by-step explanation:

Given:

  • Skim milk density at 20 °C = 1.033 kg/l
  • Light cream density at 20 °C = 1.012 kg/l
  • 1 liter = 0.264 gallons

<u>Question 2</u>

\begin{aligned}\textsf{1 gallon} & = \sf \dfrac{1}{0.264}\:liters\\\\\implies \textsf{Mass (1 gallon of skim milk)} & = \sf Density \times Volume\\& = \sf 1.033\:kg/l \times \dfrac{1}{0.264}\:l\\& = \sf 3.913\:kg\:(3\:dp)\end{aligned}

Therefore, the mass of 1 gallon of skim milk is 3.913 kg (3 dp)

---------------------------------------------------------------------------------------------

<u>Question 3</u>

Given:

  • Volume of liquid = 9 liters
  • Mass of liquid = 9.108 kg

\begin{aligned}\implies \sf Density & = \sf \dfrac{Mass}{Volume}\\\\& = \sf \dfrac{9.108\:kg}{9\:l}\\\\& = \sf 1.012\:kg/l \end{alilgned}

Therefore, the container holds light cream.

---------------------------------------------------------------------------------------------

<u>Question 4</u>

Given:

  • 15 CoffeeStops per 100,000 people
  • Population of Manhattan ≈ 1,602,000 people

\begin{aligned}\implies \textsf{Number of Coffeestops} & = \sf \dfrac{population}{density}\\\\& = \sf \dfrac{1,602,000}{100,000/15}\\\\& = \sf \dfrac{1,602,000}{100,000} \times 15\\\\& = \sf 240.3\end{aligned}

Therefore, there are 240 CoffeeStops.

---------------------------------------------------------------------------------------------

<u>Question 5</u>

Given

  • Manhattan ≈ 34 square miles

\begin{aligned}\implies \textsf{CoffeeStops density} & = \sf \dfrac{number\:of\:stores}{land\:area}\\\\& = \sf \dfrac{240}{34}\\\\& \approx \sf 7 \: \textsf{CoffeeStops per square mile}\end{aligned}

Therefore, the density of CoffeeStops is 7 per square mile.

---------------------------------------------------------------------------------------------

<u>Question 6</u>

Given:

  • Each person buys 3 cups of coffee per week

\begin{aligned}\implies \textsf{Cups served each week} & = \textsf{number of people} \times \textsf{number of cups per week}\\& = \sf 1,602,000 \times 3\\& = \sf 4,806,000\: \textsf{cups per week}\\\\\implies \textsf{Cups per day} & = \sf \dfrac{\textsf{cups per week}}{\textsf{days in a week}}\\\\& = \sf \dfrac{4,806,000}{7}\\\\& = \sf 686,571\:\textsf{(nearest whole number)}\end{aligned}

\begin{aligned}\implies \textsf{Cups served per day per shop} & = \dfrac{\textsf{cups per day}}{\textsf{number of shops}}\\\\& = \sf \dfrac{686,571}{240}\\\\& = \sf 2,861\: \textsf{(nearest whole number)} \end{aligned}

Therefore, each Manhattan CoffeeStop serves approximately 2,861 cups of coffee each day.

7 0
2 years ago
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