Its $23 per hour hopefully this helps
9514 1404 393
Answer:
1. ∠EDF = 104°
2. arc FG = 201°
3. ∠T = 60°
Step-by-step explanation:
There are a couple of angle relationships that are applicable to these problems.
- the angle where chords meet is half the sum of the measures of the intercepted arcs
- the angle where secants meet is half the difference of the measures of the intercepted arcs
The first of these applies to the first two problems.
1. ∠EDF = 1/2(arc EF + arc UG)
∠EDF = 1/2(147° +61°) = 1/2(208°)
∠EDF = 104°
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2. ∠FHG = 1/2(arc FG + arc ES)
128° = 1/2(arc FG +55°) . . . substitute given information
256° = arc FG +55° . . . . . . multiply by 2
201° = arc FG . . . . . . . . . subtract 55°
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3. For the purpose of this problem, a tangent is a special case of a secant in which both intersection points with the circle are the same point. The relation for secants still applies.
∠T = 1/2(arc FS -arc US)
∠T = 1/2(170° -50°) = 1/2(120°)
∠T = 60°
1. X/Y = Z
if x = 6, y = 2, then z = 3, not even
if x = 6, y = 3, then z = 2, even
<span>2. Z=XY </span>
so (z)^2 = 2*k (because x*y*z = 2k, where k is an integer)
<span>Sufficient, as if square of an integer is even ,then the integer is even</span>
Answer:
4,020
Step-by-step explanation:
mean = average
- Ideally, in order for us to have a 3,700 pound average, each of the four trucks would be 3,700 pounds. Added up, we would have a total of: 14,800 pounds (3,700×4)
- Let's see how much pounds we already have:
- 3,250 + 3,890 + 3,640 = 10,780
Now we need to find how much pounds we are missing: 14,800 - 10,780 =
<h2>4,020
for the fourth truck</h2>
- Let's check: 3,250 + 3,890 + 3,640 + 4,020 = 14,800
- 14,800/4 = 3,700 pounds
<h3>Good job! I hope this helps</h3>