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8_murik_8 [283]
3 years ago
14

Find the midpoint of the segment with the following endpoints. (-3,6) and (3,0)

Mathematics
1 answer:
Tresset [83]3 years ago
4 0
Answer


(-3, 3)


Step-by-Step



-3-3/2=-6/2= -3
6-0/2= 6/2 = 3

(-3,3)
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II. Using Radians to Measure Arcs and Angles
padilas [110]
Pi radians is 180 degrees.
A
1) 180/3=60
2) 270
3) 45
4) 3240
B
1) 100/180=5/9
3) 30/180=3/18
5) 1/180
C
1) (pi) cm
2) 2pi
4 0
3 years ago
The ___ is the average of the sum of the squared differences of the mean from each element in a set of numerical data.
Bess [88]

Answer:

Variance.

Step-by-step explanation:

that is the variance of the data.

The square root of the variance is the Standard Deviation.

4 0
1 year ago
PLEASEE HELP THIS IS DUE TODAY
dangina [55]

Answer:

The first one is 360 degrees. The second one is 1080.

Step-by-step explanation:

The sum of the interior angles of a quadrilateral are always 360. If you subtract 90 from 360 to get 270. Multiply 270 by 4 to get 1080.

7 0
3 years ago
The claim is that the proportion of adults who smoked a cigarette in the past week is less than 0.30​, and the sample statistics
IrinaK [193]

Answer: 0.84

Step-by-step explanation:

let p be the population proportion of adults who smoked a cigarette in the past week.

As per given , we have

H_a: p

Sample size : n= 1491

The sample proportion of adults smoked a cigarette= \hat{p}=\dfrac{x}{n}=\dfrac{462}{1491}=0.30985915493\approx0.31

The test statistic for proportion is given by :-

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

Substitute all the values , we get

z=\dfrac{0.31-0.30}{\sqrt{\dfrac{0.30(1-0.30)}{1491}}}\\\\=\dfrac{0.01}{\sqrt{0.000141}}\\\\=\dfrac{0.01}{0.011874342087}=0.84261497731\approx0.84

Hence, the value of the test statistic = 0.84

6 0
3 years ago
What is greater 16/25 or 65%
slega [8]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

65% has the greater value.  

»»————- ★ ————-««  

Here’s why:  

  • We can convert both numbers into decimals and then compare the values.

⸻⸻⸻⸻

\boxed{\text{Comparing Numbers:}}\\\\-------------\\\rightarrow\frac{16}{25}= 0.64\\\\\rightarrow 65\%=\frac{65}{100}=0.65\\ -------------\\\\\boxed{0.65 > 0.64}\\\\\text{Therefore:}\\\\\boxed{65\% > \frac{16}{25}}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

6 0
3 years ago
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