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Zielflug [23.3K]
3 years ago
11

At elevated temperatures in an automobile engine, N2 and O2 can react to yield NO, an important cause of air pollution.

Chemistry
1 answer:
Ivan3 years ago
7 0

(a) <u>7.32 moles of N₂</u>

(b) = 5.72 moles of NO

(c) 0.460 moles of O₂

Explanation:

We begin by balancing the chemical reaction involved;

N₂ + 0₂ →  2NO

The number in front of the elements or compounds indicate the mole ration involved in the reaction. One (1) mole of N2 and one (1) mole of O2 react to form two (2) moles of NO.

(a) Because the mole ratio between O₂ and N₂ is 1 : 1 then <u>7.32 moles of N₂</u> are needed to react with 7.32 mol of O₂

(b) Because the ration of N₂ and NO in the chemical equation is 1 : 2, then  (2.86 * 2) moles of NO can be formed when 2.86 mol of N₂ reacts.

= 5.72 moles of NO

(c) (b) Because the ration of O₂ and NO in the chemical equation is 1 : 2, then (0.230 * 2) moles of O₂ must react to produce 0.230 mol of NO.

= 0.460 moles of O₂

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10) In order to find the conjugate acid of a chemical you just add a hydrogen to the chemical.  
examples:  the conjugate acid of Cl⁻ is HCl, the conjugate acid of PO₄³⁻ is HPO₄²⁻, the conjugate acid of NH₃ is NH₄⁺, the conjugate acid of HCO₃⁻ is H₂CO₃, and the conjugate acid of H₂O is H₃O⁺
To find the conjugate base of a chemical you just reverse that process (take away a hydrogen).
examples: the conjugate base of H₂SO₄ is HSO₄⁻, the conjugate base of CH₃COOH is CH₃COO⁻, the conjugate base of H₃PO₄ is H₂PO₄⁻, and the conjugate base of H₂O is OH⁻.

When you identify conjugate acids and bases in a reaction you look to see what lost a proton and what gained a proton.  The chemical that gave up the proton acted as an acid and produced a conjugate base while the chemical that accepted a proton produced a conjugate acid.
Example: HCl+NaOH⇒NaCl+H₂O  The acid is HCl and its conjugate base is Cl⁻ while NaOH was the base and H₂O is the conjugate acid.  (you can ignore the sodium since it is a spectator ion).

 11) When completing acid base reactions, need to identify the acid and the base since the acid will give a proton the base creating a conjugate base of the acid and conjugate acid of the base. (You need to balance the equation after you determine what the products will be)
example: H₂SO₄+2NaOH⇒Na₂SO₄+2H₂O  (SO₄²⁻ is the conjugate base of HSO₄⁻ which is the conjugate base of H₂SO₄.  HSO⁻ is created with the first NaOH molecule and then SO₄⁻ is created with the second NaOH.)

12) All acid base reaction form a salt consisting of the cation from the base and anion from the acid.  
examples:  NaCl could have come from NaOH reacting with HCl.  K₃PO₄ could have come from KOH and H₃PO₄.

13) I don't really know how you are supposed to solve it with out knowing the Ka value of H₂S.  H₂S is a weak acid and therefore will not dissociate completely in water so the only way of being able to find the concentration of H⁺ ions that dissociate is knowing the Ka value of H₂S and using ice tables.  (Ka=[H⁺][A⁻]/[HA] and is basically the equilibrium constant for the acid when put into water where A⁻ is the conjugate base and HA is the acid).

14) Ca(OH)₂ is a strong base and will therefore dissociate completely in water.  That means that when you find the concentration of OH⁻ in solution you can multiply that by the volume of the solution (in liters) to find the number of moles of OH⁻.  Then you can divide that by 2 to find the number of moles of Ca(OH)₂ needed.  pOH=14-pH which means that pOH=4.2.  [OH⁻]=10^-pOH which means [OH⁻]=6.3x10^-5 M.  6.3x10^-5Mx3.00L=1.89x10^-4mol OH⁻ which means that (1.89x10^-4)/2=9.46x10^-5mol Ca(OH)₂.

I hope this helps.  Let me know if anything is unclear.
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