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3 years ago

Which of the following is the correct word equation for the reaction described below?

Chemistry

2 answers:

vampirchik [111]3 years ago

6 0

The answer here is a. sulfuric acid + sodium hydroxide → sodium sulfate + water

pshichka [43]3 years ago

4 0

A) sulfuric acid + sodium hydroxide → sodium sulfate + water

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What would be the major product obtained from hydroboration–oxidation of the following alkenes?

zmey [24]

Answer:

a. 3-methylbutan-2-ol

b. 2-methylcyclohexan-1-ol

Explanation:

For this reaction, we must remember that the hydroboration is an "anti-Markovnikov" reaction. This means that the "OH" will be added at the least substituted carbon of the double bond.

In the case of 2-methyl-2-butene, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore the "OH" will be added to carbon three producing 3-methylbutan-2-ol.

For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore the "OH" will be added to carbon 2 producing 2-methylcyclohexan-1-ol.

See figure 1

I hope it helps!

8 0

3 years ago

Which of the following is generally true of female bones in relationship to male bones?

gtnhenbr [62]

What are the options

6 0

3 years ago

Every atom's goal is to get ________ electrons in its valence shell.

sdas [7]

Every atom tends to form configuration of noble gas , with the 8 electrons in valence shell.

6 0

3 years ago

Covalent bonding is the ____ of electrons

taurus [48]

Answer: sharing

Reason: They do this to gain stability. The reason they don’t actually transfer is because the difference in electronegativity values are above a certain value.

8 0

3 years ago

A scientist prepared an aqueous solution of a 0.45 M weak acid. The pH of the solution was 2.72. What is the percentage ionizati

aleksandr82 [10.1K]

Answer:

0.42%

Explanation:

∵ pH = - log[H⁺].

2.72 = - log[H⁺]

∴ [H⁺] = 1.905 x 10⁻³.

∵ [H⁺] = √Ka.C

∴ [H⁺]² = Ka.C

∴ ka = [H⁺]²/C = (1.905 x 10⁻³)²/(0.45) = 8.068 x 10⁻⁶.

∵ Ka = α²C.

Where, α is the degree of dissociation.

∴ α = √(Ka/C) = √(8.065 x 10⁻⁶/0.45) = 4.234 x 10⁻³.

∴ percentage ionization of the acid = α x 100 = (4.233 x 10⁻³)(100) = 0.4233% ≅ 0.42%.

4 0

3 years ago

Read 2 more answers