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max2010maxim [7]
3 years ago
6

What is the charge of a boron ion with 5 protons and 7 electrons

Chemistry
2 answers:
zlopas [31]3 years ago
8 0
Negative, because electrons have a negative charge and there are more of them.
jolli1 [7]3 years ago
3 0
Protons are positively charge, and electrons are negative. Since there are 2 more electrons, then there is a negative 2 charge. (2-)
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Gold has a density of about 20.0g/mL this means that each milliliter has a mass of about __ grams.
qwelly [4]

Answer:

20.0 grams

Explanation:

If the density of gold is 20.0 g/mL, then we can multiply it by 1 mLto find the weight of 1 mL of gold.

20.0\frac{grams}{mL}*1mL=20.0 grams

8 0
4 years ago
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Iodine-131 is a radioactive isotope that is used as a medical tracer to study and treat the thyroid gland. This radioactive elem
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Bonjeur monseur, la french are here! it seems you have a problem with the elements on earth. lead seems correct since it is indeed a harmful material
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4 years ago
I did this on accident lol
k0ka [10]
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5 0
3 years ago
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Is 2 KNO₃ + H₂CO₃ → K₂CO₃ + 4 HNO₃ a balanced equation
krok68 [10]

Hey there!

The elements in this equation are K, N, O, H, and C.

Let's count how many of each are on each side to see if it is balanced.

K: 2 on the left, 2 on the right.

<em>N: 2 on the left, 4 on the right. </em>

<em>O: 9 on the left, 6 on the right. </em>

<em>H: 2 on the left, 4 on the right. </em>

C: 1 on the left, 1 on the right.

Notice that there are different amounts of N, O, and H on the left side and the right side.

This means that the equation is not balanced.

Hope this helps!

6 0
3 years ago
A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a
Nady [450]

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

q=mc\Delta T

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

q_{released}=q_{absorbed}\\&#10;q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T

The given mass of calorimeter has been, m_{calorimeter}=1350\;\rm g

The specific heat of the calorimeter has been, c_{calorimeter}=5.82\;\rm J/g^\circ C

The change in temperature of the calorimeter has been, \Delta T=2.87^\circ \rm C

Substituting the values for heat released:

q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\&#10;q_{released}=22,549.5\;\text J\\&#10;q_{released}}=22.54\;\rm kJ

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

6 0
3 years ago
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