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andrew11 [14]
3 years ago
11

Solve the inequality 4^2 - 25 < 0​

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

true

Step-by-step explanation:

42−25<0

−9<0

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Simplify <br>(8/14 - 2/8) + 1/7​
konstantin123 [22]

Answer:

13/28.

Step-by-step explanation:

(8/14 - 2/8) + 1/7

We can just remove the parentheses and simplify its contents:

=  4/7 - 1/4 + 1/7

= 4/7 + 1/7 - 1/4

= 5/7 - 1/4      The LCD of 7 and 4 is 28 so we have:

20/28 - 7/28

= 13/28.

7 0
3 years ago
Find the value of x in the equilateral triangle.<br> Х<br> 3 in
swat32

Answer:

x≈3.35, or the square root of 11.

Step-by-step explanation:

Use the pythagorian therom. 3²+1.5²=x²

(Half of 3 is 1.5 and the line splits it in half)

6 0
2 years ago
Choose the values of the range given the function below. {(-1, -3), (5,7). (8. -4), (-7, 3), (-5, 11)}​
lyudmila [28]

Answer:

the answer is 53454

Step-by-step explanation:

1+1=1

6 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
The vertices of a quadrilateral in the coordinate plane are known how can the perimeter of the figure be found
natta225 [31]

Answer:

d

Step-by-step explanation:

6 0
3 years ago
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