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2 years ago

15

Which of the following is a situation in which an equation cannot be solved using the quadratic formula? A.) The coefficient of

the x^2 term is zero B.) The right hand side of the equation is zero C.) The coefficient of the x term is zero D.) The degree of the polynomial is 2

1 answer:

yaroslaw [1]2 years ago

7 0

I think it would be A) The coefficient of the x^2 term is zero.

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(5 pts) A quadratic function f is given by f(x) = ax2 + bx + c where a is not 0. Select all

Vsevolod [243]

Answers:

a) True. Plug in x = 0 and it leads to y = c. Therefore, the point (0,c) is on the parabola.
b) False. Plug in y = 0 and apply the quadratic formula. One x intercept may sometimes be x = c, but it could easily be other values as well. Or perhaps you may not get any real number solutions at all. See part d) below.
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d) False. The quadratic may have one x intercept or it may not have any x intercepts at all. It depends on what the discriminant d = b^2 - 4ac is equal to. If d < 0, then we have no x intercepts. If d = 0, then we have exactly 1 x intercept. If d > 0, then we have two different x intercepts.
e) True. The vertex's x coordinate is -b/(2a). If b = 0, then the x coordinate of the vertex is 0. The vertical line x = 0 is directly on top of the y axis.

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3 years ago

light travels at 3x10 to the power of 8 meters per second. there are 8.64x10 to the power of 4 seconds in 24 hours. how many met

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Distance = velocity * time

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3 years ago

A young sumo wrestler decided to go on a diet to gain weight rapidly. He gained weight at a rate of 5.5kg a month. After 11 mont

kondaur [170]

Answer:

$W(t)=5.5t+79.5$ .

Step-by-step explanation:

Please consider the complete question.

A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. He gained weight at a rate of 5.5 kilograms per month. After 11 months, he weighed 140 kilograms. Let W(t) denote the sumo wrestler's weight W(measured in kilograms) as a function of time t (measured in months).

Since wrestler gained weight at a rate of 5.5 kilograms per month, so slope of line be 5.5.

Now, we will use point-slope form of equation as:

$y-y_1=m(x-x_1)$ , where,

m = Slope

$(x_1,y_1)$ = Given point on the line.

Upon substituting coordinates of point (11,140) in above formula, we will get:

$y-140=5.5(x-11)$

$y-140=5.5x-60.5$

$y-140+140=5.5x-60.5+140$

$y=5.5x+79.5$

Therefore, our required function would be $W(t)=5.5t+79.5$ .

3 0

3 years ago