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Two volumes of William Shakespeare stand on a bookshelf next to each other: volume one, then volume two. Each volume is 4 cm thi

Setler79 [48]

Answer:

L = 7 [cm]

Explanation:

To solve this problem we must analyze each of the distances mentioned and take into account the number of covers and thicknesses of these.

The worm crosses through the sheets of the first book, this distance can be determined by the following length analysis.

4 = P + 2*C

Where:

P = thicknesses of the pages [cm]

C = thicknesses of each cover [cm]

P = 4 - 2*(0.5)

P = 3 [cm]

The distance crossed was:

L = P + 2C + P "the pages of the first book + 2 covers + the pages of the second book"

L = 3 + (2*0.5) + 3

L = 7 [cm]

7 0

3 years ago

Where was the most recent earthquake closest to Berwyn, PA? Give some details.

Vadim26 [7]

11/23/2012 - 2.2 mag, 5.0mi depth 1.0875 mi from <span>Gloucester Township, NJ
</span>

7 0

3 years ago

Read 2 more answers

An ethernet cable is 3.80 m long and has a mass of 0.210 kg. A transverse pulse is produced by plucking one end of the taut cabl

Tasya [4]

Answer:

$T=94.54N$

Explanation:

The tension in a cable is given by:

$T=\mu v^2(1)$

Where $\mu$ is the mass density of the cable and v is the speed of the cable's pulse. These values are defined as:

$\mu=\frac{m}{L}(2)\\v=\frac{d}{t}$

The pulse makes four trips down and back along the cable, so $d=4(2L)$

$v=\frac{8L}{t}(3)$

Replacing (2) and (3) in (1), we calculate the tension in the cable:

$T=\frac{m}{L}(\frac{8L}{t})^2\\T=\frac{64mL}{t^2}\\T=\frac{64(0.21kg(3.80m))}{(0.735s)^2}\\T=94.54N$

3 0

3 years ago

How many neutrons are present in an atom of Iron-54

Flura [38]

there are 28 neutrons present

3 0

3 years ago

Suppose a 2662 kg giant seal is placed on a scale and produces a 20.0 cm compres- sion. If the seal and spring system are set in

Yuki888 [10]

Answer:

0.8976 seconds

Explanation:

The period of oscillation for the simple harmonic motion can be found using the formula ...

T = 2π√(d/g)

where d is the displacement of the spring due to the attached weight, and g is the acceleration due to gravity.

__

For d = 0.20 meters, the period is ...

T = 2π√(0.20/9.8) ≈ 0.8976 . . . . seconds

_____

<em>Additional comment</em>

The formula for the oscillator period is usually seen as ...

T = 2π√(m/k)

where m is the mass in the system and k is the spring constant. The value of the spring constant is calculated from ...

k = mg/d

Using that in the formula, we find it simplifies to ...

$T=2\pi\sqrt{\dfrac{m}{k}}=2\pi\sqrt{\dfrac{m}{\left(\dfrac{mg}{d}\right)}}=2\pi\sqrt{\dfrac{d}{g}}$

5 0

2 years ago