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3 years ago

If(s-a)=5cm,(s-b) =10cm,(s-c) =1cm.finds.

Mathematics

2 answers:

marin [14]3 years ago

5 0

Answer:

Step-by-step explanation:

yawa3891 [41]3 years ago

4 0

You have to be more specific, you should add a picture of your problem that’s your struggling with

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LiRa [457]

The coordinates of the maximum and the minimum are:
maximum(1 , 8)

minimum(-2 , -4)

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4 years ago

I need help it’s easy

Len [333]

Answer:

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4 years ago

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An attacker at the base of a castle wall 4 m high throws a rock straight up with speed 7.5 m/s from a height of 1.5 m

Sergeu [11.5K]

Answer:

a) Yes, b) $v\approx 2.686\,\frac{m}{s}$ , c) $v_{o} \approx 7.002\,\frac{m}{s}$

Step-by-step explanation:

a) The maximum height reached by the rock is:

$\Delta y = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(7.5\,\frac{m}{s} \right)^{2}}{2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)}$

$\Delta y = 2.868\,m$

$y = 1.5\,m + 2.868\,m$

$y = 4.368\,m$

Yes, the rock will exceed the top of the wall.

b) The speed when the rock reaches the top of the wall:

$v = \sqrt{\left(7.5\,\frac{m}{s} \right)^{2}+2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m-1.5\,m)}$

$v\approx 2.686\,\frac{m}{s}$

c) The initial speed required so that stone does not exceed the top of the wall is:

$v_{o} = \sqrt{\left(0\,\frac{m}{s} \right)^{2}-2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m-1.5\,m) }$

$v_{o} \approx 7.002\,\frac{m}{s}$

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4 years ago

3x^+5x+2=0 <br> need work shown plz

Alexxandr [17]

Answer:

${3x}^{2} + 5x + 2 \\ = {3x}^{2} + 3x + 2x + 2 \\ = 3x(x + 1) + 2(x + 1) \\ = (3x +2)(x + 1)$

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3 years ago

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6/9 9/12 wich one is bigger

Alexxandr [17]

Answer:

9/12

Step-by-step explanation:

because I is the biggest number

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3 years ago

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