Answer:
Joint probability table :
_____ A _____ A'
_ Y_ 0.45 ___ 0.30
_ Y'_ 0.05___ 0.20
No
No
Step-by-step explanation:
Given :
Sample, size n = 500
A = driver is under the influence of alcohol :
Y = driver is less than 30 years old
P(A) = 275 / 500 = 0.55
P(Y) = 375 / 500 = 0.75
P(AnY) = 225 / 500 = 0.45
P(YnA') = (1 - 225/375)*0.75 = 0.4 * 0.75 = 0.30
Joint probability table :
_____ A _____ A'
_ Y_ 0.45 ___ 0.30
_ Y'_ 0.05___ 0.20
To determine if it is mutually exclusive : P(AnY) = 0
P(AnY) = 0.45 ; hence, it is not mutually exclusive
For A and Y to be independent ; P(A|Y) = P(A) ;
P(A|Y) = P(AnY) / P(Y)
P(A|Y) = 0.45 / 0.75 = 0.6
Hence, A and Y are not independent.
Answer:
option A
-2x + 4y = 4
-3x + 6y = 6
Step-by-step explanation:
In option A, if the student multiply the first equation by 3 and the second equation by -2, then the equations become
-6x+12y = 12 and
6x-12y =-12
If she adds both equations, she will get 0 = 0
This means that the system has infinite number of solutions.
Hence, the student could have started with equations -2x + 4y = 4 and -3x + 6y = 6.
The constant variation of k is 40. Hope that helps.
X=-3+y is the answer I got
