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ZanzabumX [31]
4 years ago
11

the graph of the function f is shown in the xyplane above the function f is define by f(x)=mx+b,where m and b are constant which

of the following could be the graph of the function where g(x)=-mx-b?​

Mathematics
1 answer:
sasho [114]4 years ago
7 0

Answer:

Option (C)

Step-by-step explanation:

We will apply the rules of transformations in this question.

Parent function of the given line in the graph is,

f(x) = mx

If the function is f'(x) = -mx

Then the line will be inverted of reflected across the x-axis.

If the function is g(x) = -mx - b

Then the line representing function g(x) = -mx will be shifted b units downwards, similar to the graph given in Option (C).

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Write 7.25 in word form.
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Seven and a quarter or seven point twenty-five
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What kind of expression is: <br><br><br> Answer quickly, correct answer will get brainlist
Sphinxa [80]

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4 0
2 years ago
Solve the system of equations. 2x+2y+7z=9, 2x+6y+5z=7, 2x+5y+4z=9. a.z=3 y=-2 z=3 b.x=1 y=0 z=1 c.x=2 y=-1 z=0 d. x=0 y=1 z=2
I am Lyosha [343]
2x + 2y + 7z = 9.....multiply by -1
2x + 6y + 5z = 7
--------------------
-2x - 2y - 7z = -9 (result of multiplying by -1)
2x + 6y + 5z = 7
-------------------add
4y - 2z = -2

2x + 6y + 5z = 7....multiply by -1
2x + 5y + 4z = 9
-------------------
-2x - 6y - 5z = -7 (result of multiplying by -1)
2x + 5y + 4z = 9
-------------------add
-y - z = 2

4y - 2z = -2
-y - z = 2 ......multiply by -2
-----------------
4y - 2z = -2
2y + 2z = -4 (result of multiplying by -2)
----------------add
6y = -6
y = -6/6
y = -1

4y - 2z = -2
4(-1) - 2z = -2
-4 - 2z = -2
-2z = -2 + 4
-2z = 2
z = -2/2
z = -1

2x + 2y + 7z = 9
2x + 2(-1) + 7(-1) = 9
2x - 2 - 7 = 9
2x - 9 = 9
2x = 9 + 9
2x = 18
x = 18/2
x = 9

solution is : x = 9, y = -1, and z = -1

I am not getting any of ur answer choices....but when I sub my answer choices back into all 3 of the original equations, they come out true
5 0
3 years ago
If enrollment increases by approximately the same
Tanya [424]

Given:

The enrollment increases by approximately the same percentage between 2000 and 2010 as it decreased between 1950 and 1960.

To find:

The expected enrollment in 2010.

Solution:

Percentage decrease formula:

\%\text{ decrease}=\dfrac{\text{Initial value - New value}}{\text{Initial value}}\times 100

The percentage decrease in between 1950 and 1960 is:

\%\text{ decrease}=\dfrac{4-3.5}{4}\times 100

\%\text{ decrease}=\dfrac{0.5}{4}\times 100

\%\text{ decrease}=\dfrac{50}{4}

\%\text{ decrease}=12.5

The enrollment decreased by 12.5% between 1950 and 1960. So, the enrollment increases by 12.5% between 2000 and 2010.

The expected enrollment in 2010 is:

\text{Expected enrollment}=7+\dfrac{12.5}{100}\times 7

\text{Expected enrollment}=7+0.875

\text{Expected enrollment}=7.875

Therefore, the expected enrollment in 2010 is 7.875 thousands.

4 0
3 years ago
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