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3 years ago

Factor: d2 + 16dm + 64m2

Mathematics

2 answers:

nika2105 [10]3 years ago

5 0

d^2 + 16dm + 64m^2

64m^2 + 16dm + d^2

Note: This polynomial is already in lowest terms. It cannot be factored. Are you sure that you posted the entire, correct problem?

lutik1710 [3]3 years ago

3 0

Answer:

$(d + 8m)^2$

Step-by-step explanation:

$d^2 + 16dm + 64 m^2 = (d + 8m)^2$

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Part 2

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Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

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