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olga_2 [115]
3 years ago
11

A teacher writes the following product on the board: \qquad (3x^2)(4x) = 12x^3(3x 2 )(4x)=12x 3 left parenthesis, 3, x, squared,

right parenthesis, left parenthesis, 4, x, right parenthesis, equals, 12, x, cubed Miles concludes that 3x^23x 2 3, x, squared is a factor of 12x^312x 3 12, x, cubed. Jude concludes that 12x^312x 3 12, x, cubed is divisible by 4x4x4, x.
Mathematics
2 answers:
swat323 years ago
7 0

Answer:

Both students are right.

Step-by-step explanation:

The product that the teacher wrote on the board is

\qquad (3x^2)(4x) = 12x^3

One of his students called Miles, conclude that

3 {x}^{2}

is a factor of

12 {x}^{3}

This is very true because from the given product both 3x² and 4x are factors of 12x³.

Another student , Jude also concludes that 12x³ is divsible by 4x.

This is also true because:

\frac{12 {x}^{3} }{4x}  = 3 {x}^{2}

Hence both students are correct.

tigry1 [53]3 years ago
5 0

Answer:

4x4x4x45x5x6x67

Step-by-step explanation:

keireww

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Answer:

x2-6=5x

10x=5x

50x-6=44x

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2 years ago
20 PTS What is the sixth term of the sequence shown in the table? Term Value 1 –46,656 2 7,776 3 –1,296 4 216 5 6 {SEE IMAGE}
olganol [36]

Answer:

a₆ = 6

Step-by-step explanation:

There is a common ratio r between consecutive terms in the sequence, that is

r = \frac{216}{-1296} = \frac{-1296}{7776} = \frac{7776}{-46656} = - \frac{1}{6}

This indicates the sequence is geometric.

To obtain any term in the sequence, multiply the previous term by r, thus

a₅ = 216 × - \frac{1}{6} = - 36

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8 0
3 years ago
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Vinvika [58]
10 runners ran fewer than 4 km 
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2 years ago
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Find the exact values of sin A and cos A. Write fractions in lowest terms. (5 points) A right triangle ABC is shown. Leg AC has
swat32

sin\ A = \frac{4}{5}\\\\cos\ A = \frac{3}{5}

<em><u>Solution:</u></em>

Given a right triangle ABC

The figure is attached below

From given,

AC = Base = 33

BC = Perpendicular = 44

AB = hyptotenuse = 55

We know that,

Sin\ A = \frac{perpendicular}{hypotenuse}\\\\Sin\ A = \frac{44}{55}\\\\Sin\ A = \frac{4}{5}

Also,

cos\ A = \frac{base}{hypotenuse}\\\\cos\ A = \frac{33}{55}\\\\cos\ A = \frac{3}{5}

Thus the values are found

6 0
3 years ago
Pls help me with this?
wel

Answer:

<u>C. 3</u>

Step-by-step explanation:

A^2+B^2=C^2

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A^2=9

A=3

5 0
2 years ago
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