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3 years ago

What are the five main forms of energy

Chemistry

2 answers:

babunello [35]3 years ago

6 0

Thermal Energy, Electrical Energy, Light, Sound, Nuclear Energy, and Chemical Energy

gtnhenbr [62]3 years ago

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Light heat mechanical gravitational electrical sound chemical atomic or nuclear

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24. When the equation

serg [7]

Answer:

Explanation:

Explanation:

The reaction expression is given as:

Al(OH)₃ + HNO₃ → H₂O + Al(NO₃)₃

To solve this problem, let us assign coefficient a,b,c and d to each specie;

aAl(OH)₃ + bHNO₃ → cH₂O + dAl(NO₃)₃

Conserving Al : a = d

O: 3a + 3b = c + 9d

H: 3a + b = 2c

N: b = 3d

let a = 1 , d = 1, b = 3 , c = 3

Multiply through by 3;

a = 1, b = 3, c = 3 and d = 1

Al(OH)₃ + 3HNO₃ → 3H₂O + Al(NO₃)₃

7 0

2 years ago

Read 2 more answers

Elias serves a volleyball at a velocity of 16 m/s. The mass of the volleyball is 0.27 kg. What is the height of the volleyball a

frosja888 [35]

Answer:

2,7 m

Explanation:

You can solve this doing an energy balance:

$m*g*h-\frac{1}{2} *m*v^{2} =41,7[J]$

Solving this equation to get h:

$\frac{41,7- \frac{1}{2} *m*v^{2} }{m*g}=h$

Replacing the values and solving brings to 2,7 m

6 0

3 years ago

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The chemical shift of the CH3 protons in diethylether is δ = 1.16 and that of the CH2 protons is 3.36. What is the difference in

grandymaker [24]

Answer:

Where Blocal = local magnetic field between the two regions of the molecule

Blocal = (1-σ)B0

ΔBlocal = (1-σ1)B0 - (1-σ2)B0 = (σ2 - σ1)B0 = ΔσB0 ≈ ΔδB0 x 10∧-6

= (3.36-1.16) x 10∧-6 x B0 = 2.20 x 10∧-6B0

(a) ΔBlocal = 2.20 x 10∧-6 x 1.9T = 4.2 μT

(b) ΔBlocal = 2.20 x 10∧-6 x 16.5T = 36.3 μT

Explanation:

5 0

2 years ago

Based on its location on the periodic table, which element would be most likely to form a negative ion?

Pavlova-9 [17]

<span>Fluorine ONLY form\s an ion with a -1 charge. The other three are metals, and metals for positively charged ions.</span>

7 0

3 years ago

Read 2 more answers

Calculate either [ H 3 O + ] or [ OH − ] for each of the solutions.

STALIN [3.7K]

Answer: Solution A : $[H_3O^+]=0.300\times 10^{-7}M$

Solution B : $[OH^-]=0.107\times 10^{-5}M$

Solution C : $[OH^-]=0.177\times 10^{-10}M$

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration and pOH is calculated by taking negative logarithm of hydroxide ion concentration.

$pH=-\log[H_3O^+]$

$pOH=-log[OH^-}$

$pH+pOH=14$

$[H_3O^+][OH^-]=10^{-14}$

a. Solution A: $[OH^-]=3.33\times 10^{-7}M$

$[H_3O^+]=\frac{10^{-14}}{3.33\times 10^{-7}}=0.300\times 10^{-7}M$

b. Solution B : $[H_3O^+]=9.33\times 10^{-9}M$

$[OH^-]=\frac{10^{-14}}{9.33\times 10^{-9}}=0.107\times 10^{-5}M$

c. Solution C : $[H_3O^+]=5.65\times 10^{-4}M$

$[OH^-]=\frac{10^{-14}}{5.65\times 10^{-4}}=0.177\times 10^{-10}M$

7 0

2 years ago