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jeka57 [31]
3 years ago
8

A 65kg person has a weight of

Physics
2 answers:
sergij07 [2.7K]3 years ago
7 0

If you are looking for the metric term for weight, it would be weighed in Newtons, and that would be 637 Newtons.

If you are looking for pounds, it would be 143 lbs.

yawa3891 [41]3 years ago
6 0

Answer:

So on Earth, with its 9.8 metre per second gravity, a person with a mass of 65 kilograms actually weighs 637 Newtons. Acceleration due to gravity on the Moon is about a sixth of earth, 1.622 meters per second. As a result a person with a mass of 65 kilograms on the Moon would actually weigh 105.43 Newtons.

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And air rifle pellet of mass 2 g Is fired into a block of modelling clay mounted on a model railway track. The trunk and modelli
Anna007 [38]

Answer:

0.0816 kgm/s

Explanation:

From the question,

Momentum of the pellet just before it hits the modelling clay is = (mass of the pellet+ mass of the truck clay)×initial velocity of pellet.

P =(M+m)u...................... Equation 1

Where P =  initial momentum of the pellet, m = mass of the pellet, u = initial speed of the pillet, M = mass of the truck

Given: m = 2 g = 2/1000 kg = 0.002 kg, u = 0.8 m/s, M = 0.1 kg

Substitute these values into equation 1

P = (0.002+0.1)0.8

P = (0.102)0.8

P = 0.0816 kgm/s

4 0
3 years ago
A 0.140-kg baseball is dropped from rest from a height of 1.8 m above the ground. It rebounds to a height of 1.4 m. What change
aliina [53]

Answer:

\Delta p=-1.56\ kg-m/s

Explanation:

It is given that,

Mass of the baseball, m = 0.14 kg

It is dropped form a height of 1.8 m above the ground. Let u is the velocity when it hits the ground. Using the conservation of energy as :

u=\sqrt{2gh}

h = 1.8 m  

u=\sqrt{2\times 9.8\times 1.8}

u = 5.93 m/s

Let v is the speed of the ball when it rebounds. Again using the conservation of energy to find it :

v=\sqrt{2gh'}

h' = 1.4 m  

v=-\sqrt{2\times 9.8\times 1.4}

v = -5.23 m/s

The change in the momentum of the ball is given by :

\Delta p=m(v-u)

\Delta p=0.14(-5.23-5.93)

\Delta p=-1.56\ kg-m/s

So, the change in the ball's momentum occurs when the ball hits the ground is 1.56 kg-m/s. Hence, this is the required solution.

4 0
4 years ago
The energy difference in these two conformations has been measured to be about 23 kj per mole. how much of this energy differenc
Phantasy [73]

Answer:

The answer is 7.8 kJ / mol.

Explanation:

Energy = (number of methyl group) (Gauche interactions)(3.8kJ/mol per interaction)

           = (2)(2)(3.8 kJ / mol)

            = 15.2 kJ / mol.

The energy  = (number of methyl group) - ( energy of gauche interactions)

                    = (23 kJ/mol) - 15.2 kJ/mol

                    = 7.8 kJ / mol.

8 0
3 years ago
A polarized Light of intensity I0 is incident on an analyzer. What should the angle between the axis of polarization of the ligh
Svetradugi [14.3K]

Answer:

The the angle between the axis of polarization of the light and the transmission axis of the analyzer is 52⁰.

Explanation:

Given;

I₀  as incident light intensity

The intensity of a linearly polarized light passing through a polarizer is given by Malus' law:

I = I₀Cos²θ

where;

I is the intensity after passing through the analyzer

θ is the the angle between the axis of polarization of the light and the transmission axis of the analyzer.

If 38% of the total intensity is transmitted, then I = 38% of I₀ = 0.38I₀

0.38I₀ = I₀Cos²θ

0.38 = Cos²θ

Cosθ = √0.38

Cosθ = 0.6164

θ  = Cos⁻¹ (0.6164)

θ  = 51.95° = 52⁰

Therefore, the angle between the axis of polarization of the light and the transmission axis of the analyzer to allow 38% of the total intensity to be transmitted is 52⁰.

3 0
3 years ago
5. How much time does it take for a bird flying at a speed of 45 kilometers per hour to travel a
Lyrx [107]

Answer:

40h

Explanation:

Use the velocity formula to solve

v = \frac{d}{t}

In this question, you are given velocity v = 45km/h, and you are given a distance, d = 1800km.  Time in this question is what you'll need to find.

Start by rearranging the velocity formula, to isolate for t.

v = \frac{d}{t}

Start by multiplying both sides by t

v(t) = \frac{d}{t}(t)\\\\vt = d

Then divide both sides by v.

vt\frac{1}{v} = d/v\\ \\t = \frac{d}{v}

Now that you've isolated for time, sub in your values and calculate.

t = \frac{d}{v} = \frac{1800km}{45km/h} = 40 h

8 0
3 years ago
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