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2 years ago

Find the slop that gos through (-8,9) and (-8,-7)

Mathematics

1 answer:

BaLLatris [955]2 years ago

3 0

The slope is 16/0 which means it is undefined

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Show that tangent is an odd function.Use the figure in your proof.

svlad2 [7]

We have to prove that the tangent is an odd function.

If the tangent is an odd function, the following condition should be satisfied:

$\tan(t)=-\tan(-t)$

From the figure we can see that the tangent can be expressed as:

We can start then from tan(t) and will try to arrive to -tan(-t):

$\begin{gathered} \tan(t)=\frac{\sin(t)}{cos(t)}=\frac{y}{x} \\ \tan(t)=\frac{-(-y)}{x}=\frac{-\sin(-t)}{\cos(-t)} \\ \tan(t)=-\frac{\sin(-t)}{\cos(-t)} \\ \tan(t)=-\tan(-t) \end{gathered}$

We have arrived to the condition for odd functions, so we have just proved that the tangent function is an odd function.

7 0

1 year ago

Plz help!! if f(x)=1/x and g(x)=x+3, which of the following is the graph of (f*g)(x)

Nataly [62]

Answer:

Step-by-step explanation:

the first one is correct

6 0

3 years ago

The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the whole circle to the ar

mafiozo [28]

Answer:

$Ratio = \frac{R^2 - r^2 }{ r^2}$

Step-by-step explanation:

Given

See attachment for circles

Required

Ratio of the outer sector to inner sector

The area of a sector is:

$Area = \frac{\theta}{360}\pi r^2$

For the inner circle

$r \to radius$

The sector of the inner circle has the following area

$A_1 = \frac{\theta}{360}\pi r^2$

For the whole circle

$R \to Radius$

The sector of the outer sector has the following area

$A_2 = \frac{\theta}{360}\pi (R^2 - r^2)$

So, the ratio of the outer sector to the inner sector is:

$Ratio = A_2 : A_1$

$Ratio = \frac{\theta}{360}\pi (R^2 - r^2) : \frac{\theta}{360}\pi r^2$

Cancel out common factor

$Ratio = R^2 - r^2 : r^2$

Express as fraction

$Ratio = \frac{R^2 - r^2 }{ r^2}$

6 0

2 years ago

Help please need help with this stuff thank you again for helping

Alex777 [14]

Slope intercept form: y = mx + b

Where m = slope and b = y-intercept.

By looking at the graph, we can see that the line cuts at 1/2 on the y-axis, therefore eliminating option D.

So now we have: y = mx + 1/2

Next, we'll find the slope. $\frac{y_2-y_1}{x_2-x_1}$

Plug the coordinates into the formula.

$\frac{3-(-2)}{4-(-4)}= \frac{5}{8}$

So our slope is 5/8 and the y-intercept is 1/2.

Option A is the answer.

6 0

3 years ago

What is the product of 2.4 x 103 and 1.5 x 103?

aleksandrvk [35]

Answer:

Step-by-step explanation:

38192.4

6 0

3 years ago

Find the slop that gos through (-8,9) and (-8,-7)​

Find the slop that gos through (-8,9) and (-8,-7)