See picture for questions 2 and 3

How many arcseconds are in 1°? B) 360 A) 60 C) 3,600 D) 100 E) 10,000

jenyasd209 [6]

Answer:

C) 3,600

Explanation:

An arcsecond is equal to 1/3600 of a degree. Hence, the inverse will give the number of arcsecond in a degree. An arcsecond is one of the ways to measure angular measurement

$1\ arcminute=\frac{1}{60}\ degree\\\Rightarrow 1\ degree=60\ arcminute$

$\\\Rightarrow 1\ degree=60\times 60\ arcsecond\\\Rightarrow 1\degree=3600\ arcsecond$

5 0

3 years ago

Answer those 2 questions.

Tanya [424]

Answer:

Q1: c

Q2: a

Explanation:

you can tell the factors by looking at the formulas for kinetic and potential energy

for question 1 look at the formula for kinetic energy

$KE=\frac{1}{2} mv^{2}$

the variables needed in order to calculate an object's kinetic energy are mass and velocity.

hence, when mass and velocity changes, kinetic energy changes, showing that mass and velocity are the factors affecting kinetic energy

same thing for the second question

$PE = mgh$

as g (acceleration due to gravity) is considered constant (10 $m/s^{2}$ ) it will not be considered as a factor

and thus, the factors affecting potential energy are mass and height

8 0

3 years ago

An object with total mass mtotal = 16.2 kg is sitting at rest when it explodes into three pieces. One piece with mass m1 = 4.7 k

vichka [17]

Answer:

1.) 0 kgm/s

2) 6.3 kg

3) -0.0978 m/s

4)

5)

6)

An object with total mass mtotal = 16.2 kg is sitting at rest when it explodes into three pieces. One piece with mass m1 = 4.7 kg moves up and to the left at an angle of θ1 = 23° above the –x axis with a speed of v1 = 25.4 m/s. A second piece with mass m2 = 5.2 kg moves down and to the right an angle of θ2 = 28° to the right of the -y axis at a speed of v2 = 23.8 m/s.

2) What is the mass of the third piece?

3) What is the x-component of the velocity of the third piece?

4) What is the y-component of the velocity of the third piece?

5) What is the magnitude of the velocity of the center of mass of the pieces after the collision?

6) Calculate the increase in kinetic energy of the pieces during the explosion

Explanation:

Since explosions and collisions follow the law of conservation of Momentum.

1) Magnitude of the final momentum of the system = Magnitude of the initial momentum of the system

Since the body was initially at rest,

Magnitude of the initial momentum of the system = 0 kgm/s

Hence, Magnitude of the final momentum of the system is also equal to 0 kgm/s.

2) mass of the third piece

Sum of all the masses = 16.2 kg

4.7 + 5.2 + c = 16.2

c = 6.3 kg

3) doing an x-component balance on momentum

(4.7)×(-25.4 cos 23) + (5.2)×(23.8 cos 28) + (6.3)(v) = 0

-0.6163 + 6.3v = 0

v = -0.0978 m/s

Hope this Helps!!!

4 0

4 years ago

Energy

Ahat [919]

I think the answer may be D- mechanical

7 0

4 years ago

Read 2 more answers

A cylindrical bucket, open at the top, is 28.0 cm high and 11.0 cm in diameter. A circular hole with a cross-sectional area 1.55

svlad2 [7]

Answer:

so height is 0.1283 m

Explanation:

given data

height = 28 cm

diameter = 11 cm

cross-sectional area = 1.55 cm2

water flow rate = 2.46×10^−4 m3/s

to find out

How high will the water in the bucket rise

solution

we know that here

potential energy = kinetic energy

mgh = 1/2 mv²

multiply both sides by the 2 and we get

2mgh=mv²

solve it we get

√(2gh) = v ....................1

h = v²/2g ...............2

and

flow rate = A V

2.46×10^−4 = V 1.55×10^−4

V = 1.5870 m/s

so from 2

h = v²/2g

h = 1.5870²/ 2(9.81)

h = 0.1283 m

so height is 0.1283 m

6 0

4 years ago