Using:
v = Aωcos(ωt), at t = 0, A = 2.3 m and v = 15 m/s
ω = 15/2.3
ω = 6.52 rad/s
Answer: r = 1.33 × 10^-5 mm
Explanation: The force per unit length of 2 current carrying conductor is given by the formulae below.
F/L = (u×I1×I2) /(2πr)
Where F/L = force per unit length = 7.73×10^-5mm = 0.0775 mm.
I1 = current on the first conductor = 4.27A
I2 = current on the second conductor = 1.19A
r = distance between both conductors.
u = permeability of free space = 1.25×10^-6
By substituting parameters, we have that
0.0775 = 1.25×10^-6 × 4.27 × 1.19/ 2πr
By cross multiplication
0.0775 ×2πr = 1.25×10^-6 × 4.27 × 1.19
r = 1.25×10^-6 × 4.27 × 1.19/ 0.0775 ×2π
r = 0.00000635162 / 0.0775 ×2π
r = 1.33 × 10^-5 mm
The time it takes the Polonium-194 to decay to 1/16 of its original amount is 2.8 seconds.
<h3>What is half-life?</h3>
half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay
To calculate the time it takes the sample of Polonium-196 to decay to 1/16 of its original amount, we use the formula below
Formula:
- = R/R'......... Equation 1
Where:
- n = Total number of time it takes Polonium-194 to decay to 1/16 of its original amount
- t = Half-life of Polonium-194
- R = Original amount of Polonium-194
- R' = Amount of Polonium-194 after decay
From the question,
Given:
Substitute these values into equation 1 and solve for n
Equating the base,
- n/0.7 = 4
- n = 0.7×4
- n = 2.8 seconds.
Hence, the time it takes the Polonium-194 to decay is 2.8 seconds.
Learn more about half-life here: brainly.com/question/25750315
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