Question

Chegg A “black hole” theoretically has an escape velocity that is greater or equal to the velocity of light (3 x 108 m/s). It the effective mass of the black hole is equal to the mass of the Sun (2 x 1030 kg), what is the effective “radius” (called the “Schwarzschild radius” of the black hole

Answer 1

Answer:

2966.257 m

Explanation:

c = Speed of light = 3×10⁸ m/s

M = Mass of black hole = 2×10³⁰ kg

G = Gravitational constant = 6.67408 × 10⁻¹¹ m³/ kg s²

Schwarzschild radius

$r_s=\frac{2MG}{c^2}\\\Rightarrow r_s=\frac{2\times 2\times 10^{30}\times 6.67408\times 10^{-11}}{(3\times 10^{8})^2}\\\Rightarrow r_s=2966.257\ m$

∴Schwarzschild radius of the black hole is 2966.257 m