The value of

,

, and

for each schools is given in the first picture below.

is the lower quartile

is the median

is the upper quartile
School A:
Minimum value is 2
Maximum value is 22
The lower quartile is 2.5
The median is 10
The upper quartile is 15.5
School B:
Minimum value is 9
Maximum value is 20
The lower quartile is 12
The median is 16
The upper quartile is 18
The box plot for each school is shown in the second picture
Box plot for school A isn't symmetrical. The data tails on the right
Box plot for school B isn't symmetrical. The data tails on the left
A. She would use hours to minutes, which you can do by dividing 22 by 60.
b. 22 / 60 = .366 repeating, or about .37 per minute
Answer:
-24.1t^2+3
Step-by-step explanation:
Answer:
The Answer is: There are 8 small boxes and 9 large boxes. See explanation below for variables and variable definitions.
Step-by-step explanation:
Let s = small boxes. Let b = large boxes.
s + b = 17
You can solve for s:
s = 17 - b
You can solve for b:
b = 17 - s
10 times the number of small boxes plus 24 times the number of large boxes is equal to 296 granola bars.
10s + 24b = 296
Substitute:
10(17 - b) + 24b = 296
170 - 10b + 24b = 296
14b = 296 - 170
14b = 126
b = 126 / 14 = 9 large boxes
Find the number of small boxes, s:
s = 17 - b = 17 - 9 = 8 small boxes
There are 8 small boxes and 9 large boxes.
Proof:
10(8) + 24(9) = 296
80 + 216 = 296
296 = 296
I believe 5 different ways. The options being two packs of 9-one pack of 9 and 3 packs of 3- 1 pack of 9, 2 packs of 3 and 3 singles- one pack of 9, one pack of 3, and 6 singles- and then one pack of 9 and 9 singles.
Hope this helped!