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pogonyaev
3 years ago
14

Abby has a begging of $720 in her checking acount. she rites a checks for $250 and $350 respetivly and diposite $500. what is he

r new balance
hurry plzzzzzz help
Mathematics
1 answer:
Andreas93 [3]3 years ago
3 0

720 - 350 - 250 = 120
120 + 500 = 620
her new total is $620
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Answer:

Step-by-step explanation:

Hello!

The objective is to test if rising the process temperature reduces the thickness of the plastic film that coats a substrate material To do so, two samples of substrates are coated at different temperatures:

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Sample 2

X₂: Thickness of the plastic film after the substrate is coated at 150F

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Then the hypotheses are:

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H₁: μ₂ < μ₁

α:0.05 (there is no α level stated so I've chosen the most common one)

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This test is one-tailed to the left, meaning that you'll reject the null hypothesis at small values of t. The p-value is also one-tailed and has the same direction as the test. To calculate it you have to first calculate the degrees of freedom of the Welch's t:

Df_w= \frac{(\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} )^2}{\frac{(\frac{S^2_1}{n_1})^2 }{n_1-1}+\frac{(\frac{S^2_2}{n_2} )^2}{n_2-1}  }

Df_w= \frac{(\frac{5.08^2}{11} +\frac{20.15^2}{13} )^2}{\frac{(\frac{5.08^2}{11})^2 }{10} +\frac{(\frac{20.15^2}{13} )^2}{12} } = 13.78

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P(t₁₃≤0.072)= 0.4718

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If the p-value ≤ α, the decision is to reject the null hypothesis.

If the p-value > α, the decision is to not reject the null hypothesis.

The p-value is greater than the significance level, so the decision is to nor reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to support the claim that the average thickness pf the plastic coat processed at 150F is less than the average thickness pf the plastic coat processed at 125F.

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