As per Newton's law of inertia we can say every object will move in its state of motion either in the state of rest or will move with same constant velocity until some unbalanced external force will act upon it
so here we have to fill the space which says that stationary object can start or moving object will change its direction only in which case
so here the correct answer should be Unbalanced Force condition we will obtain such situation.
so we have
<u>Unbalance force</u> can cause a stationary object to start moving or a moving object to change its speed or direction or both.
Answer: The partial pressure of
if the total pressure of the mixture is 3.9 atm is 0.975 atm
Explanation:
According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.
![p_A=x_A\times P_T](https://tex.z-dn.net/?f=p_A%3Dx_A%5Ctimes%20P_T)
where, x = mole fraction of nitrogen in solution = 0.25
= partial pressure of nitrogen = ?
= Total pressure = 3.9 atm
Putting in the values :
![p_A=0.25\times 3.9=0.975atm](https://tex.z-dn.net/?f=p_A%3D0.25%5Ctimes%203.9%3D0.975atm)
The partial pressure of
is 0.975 atm
Answer:
2m/s²
Explanation:
- V=Vstart+at
- rewrite that to find a so a=(V-Vstart)/t
part A of graph
part B of graph
the average between the two is both answers added divided by the number of answers
- (4m/s²–0m/s²)/2
- 4m/s²/2
- 2m/s²
Answer:
4.245s
Explanation:
Given that,
Hypothetical value of speed of light in a vacuum is 18 m/s
Speed of the car, 14 m/s
Time given is 6.76 s, and we're asked to find the observed time, T
The relationship between the two times can be given as
T = t / √[1 - (v²/c²)]
The missing variable were looking for is t, and we can find it if we rearrange the formula and make t the subject
t = T / √[1 - (v²/c²)]
And now, we substitute the values and insert into the equation
t = 6.76 * √[1 - (14²/18²)]
t = 6.76 * √[1 - (196/324)]
t = 6.76 * √(1 - 0.605)
t = 6.76 * √0.395
t = 6.76 * 0.628
t = 4.245 s
Therefore, the time the driver measures for the trip is 4.245s
a) mass
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