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Anna71 [15]
3 years ago
11

A truck hits a brick wall with a force of 120 N. The collision takes 2.0 seconds.

Physics
1 answer:
levacccp [35]3 years ago
7 0
Impulse=force*time
impluse=120N*2.0s
impluse=240 Ns
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An open organ pipe of length 0.47328 m and another pipe closed at one end of length 0.702821 m are sounded together. What beat f
sineoko [7]

Answer:

fb = 240.35 Hz

Explanation:

In order to calculate the beat frequency generated by the first modes of each, organ and tube, you use the following formulas for the fundamental frequencies.

Open tube:

f=\frac{v_s}{2L}         (1)

vs: speed of sound = 343m/s

L: length of the open tube = 0.47328m

You replace in the equation (1):

f=\frac{343m/s}{2(0.47228m)}=362.36Hz      

Closed tube:

f'=\frac{v_s}{4L'}

L': length of the closed tube = 0.702821m

f'=\frac{343m/s}{4(0.702821m)}=122.00Hz

Next, you use the following formula for the beat frequency:

f_b=|f-f'|=|362.36Hz-122.00Hz|=240.35Hz

The beat frequency generated by the first overtone pf the closed pipe and the fundamental of the open pipe is 240.35Hz

7 0
3 years ago
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kondaur [170]
Gravity if I’m not mistaken
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Calculate the potential difference across a 10 ohm register carrying a current of 2.5 ampere​
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Answer:

using ohm's law

V=IR

V= 10 X 0.2

V = 2 Volt.

Explanation:

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Refer to the diagram. Which answer correctly labels the water between the equator and the North Pole?
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B.---A. warm water B. thermocline C. cold water
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3 years ago
What mass of electrons would be required to just neutralize the charge of 4.8 g of protons?
suter [353]
Let's calculate the total charge of M=4.8 g=0.0048 kg of protons.
Each proton has a charge of q=1.6 \cdot 10^{-19} C, and a mass of m_p = 1.67 \cdot 10^{-27}kg. So, the number of protons is
N_p =  \frac{M}{m_p}= \frac{0.0048 kg}{1.67 \cdot 10^{-27}kg}=2.87 \cdot 10^{24} And so the total charge of these protons is Q_p = qN_p = (1.6 \cdot 10^{-19}C)(2.87 \cdot 10^{24})=4.6\cdot 10^5 C

So, the neutralize this charge, we must have N_e electrons such that their total charge is
Q_e = -4.6 \cdot 10^5 C
Since the charge of each electron is q_e = -1.6 \cdot 10^{-19}C, the number of electrons needed is
N_e =  \frac{Q_e}{q}= \frac{-4.6 \cdot 10^5 C}{-1.6 \cdot 10^{-19}C}=2.87 \cdot 10^{24}
which is the same as the number of protons (because proton and electron have same charge magnitude). Since the mass of a single electron is m_e=9.1 \cdot 10^{-31}kg, the total mass of electrons should be
M_e = N_e m_e = (2.87 \cdot 10^{24})(9.1 \cdot 10^{-31}kg)=2.6 \cdot 10^{-6}kg
6 0
2 years ago
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