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3 years ago

What is frictional force?how to Express frictional force?

Physics

1 answer:

Kay [80]3 years ago

5 0

Answer:

Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact.

Coefficient of friction, ratio of the frictional force resisting the motion of two surfaces in contact to the normal force pressing the two surfaces together. It is usually symbolized by the Greek letter mu (μ). Mathematically, μ = F/N, where F is the frictional force and N is the normal force.

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If sonic the hedgehog runs 40 meters in 5 seconds, what is his speed?

hoa [83]

Answer:

8m/s

Explanation:

Sonic can go WAAAAAAAAAAAAY faster, but he must be taking a jog. All jokes aside, Divide 40 by 5. You get 8 meters per second or 17.9 mph.

6 0

4 years ago

A 52 kg person is running 2.5 m/s. What is their momentum?

aivan3 [116]

Answer:

130kg/ms

Explanation:

given data
mass,52kg
velocity,2.5m/s

momentum?
from momentum
M=mv

6 0

3 years ago

Read 2 more answers

The particles in an object move in (many/ two directions)

pentagon [3]

Answer:

They are negitive

Explanation:

Im pretty sure

8 0

4 years ago

Calculate the wavelength (in nm) of light that produces its first minimum at an angle of 21.0° when falling on a single slit of

Cerrena [4.2K]

To solve this problem it is necessary to apply the related concepts to the principle of overlap, specifically to single slit diffraction experiment concept.

Mathematically this can be expressed as:

$dsin\theta = m\lambda$

Where,

d = Width of the slit

$\lambda =$ Wavelength

$\theta =$ Angle relative to the original direction of the light

m = Any integer which represent the order of the equation (number of repetition of the spectrum)

To solve the problem we need to rearrange the equation and find the wavelength

$\lambda = \frac{dsin\theta}{m}$

Our values are given as,

$d = 1.46\mu m = 1.46*10^{-6}m$

$\theta = 21\°$

$m = 1$

Replacing in our equation we have,

$\lambda = \frac{dsin\theta}{m}$

$\lambda = \frac{(1.46*10^{-6})sin(21)}{1}$

$\lambda = 5.232*10^{-7}m$

$\lambda = 523.2nm$

Therefore the wavelength is 523.2nm

7 0

4 years ago

How are dwarf planets different from true planets?

morpeh [17]

Answer:

The only difference between a planet and a dwarf planet is the area surrounding each celestial body. A dwarf planet has not cleared the area around its orbit, while a planet has.

Explanation:

the three criteria of the IAU for a full-sized planet are: It is in orbit around the Sun. It has sufficient mass to assume hydrostatic equilibrium (a nearly round shape). It has "cleared the neighborhood" around its orbit .

3 0

3 years ago