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Vesna [10]
3 years ago
6

Question 4

Chemistry
1 answer:
mixer [17]3 years ago
5 0

Answer:

pH = 10.87

Explanation:

You can find pH of a buffer (Mixture of a weak base, X, and its conjugate acid, HX) by using H-H equation:

pH = pKa + log [X] / [HX]

pKb is -log Kb = 3.13

Using Hint pKw = pKa + pKb (pKw = 14)

pKw = pKa + pKb

14 - 3.13 = pKa

10.87 = pKa

Replacing in H-H equation:

pH = 10.87 + log [0.42M] / [0.42]

pH = 10.87 + log 1

<h3>pH = 10.87</h3>

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\\ \sf\longmapsto 14u+3(1u)

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<h2>#keep learning </h2><h3>hope makatulong</h3>
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