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3 years ago

Can a solution of Sn(NO3)2 be stored in an aluminum container?

1 answer:

3 0

I believe a solution of Sn(NO3)2 can not be stored in an aluminium container because Aluminium is higher in the reactivity series compared to Tin (Sn). Therefore, Aluminium is more reactive than Tin and hence aluminium will displace Tin from its salt forming Aluminium nitrate and Tin metal. Thus storing Tin nitrate in an aluminium container will cause the "eating away' of the container.

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If an element gives away an electron, will it form a positive ion or a negative ion?

Elan Coil [88]

Answer:

posotive

Explanation:

electrons give off negative pulse so take one away

8 0

3 years ago

Hello,

nikitadnepr [17]

Answer:

$a)\ 2FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3\\b)\ Decomposition\ Reaction$

Explanation:

Ferrous Sulphate $(FeSO4)$ is generally found as Lime-Green Crystals. On heating, these crystals almost immediately turn white-yellow. They then, break down to produce an anhydrous mixture of Sulphur Trioxide $(SO_3)$ , Sulphur Dioxide $(SO_2)$ as well as Ferric Oxide $(Fe_2O_3)$ .

We can hence, frame a skeletal equation of this reaction and try to balance it.

Hence,

$FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3$

Now,

a)In order to balance it through the 'Hit &Trial Method', we'll follow a series of steps:

1. First, lets compare the number of Fe (Iron) atoms on the RHS and LHS. We find that, the no. of Fe Atoms on the RHS is twice the number of Fe Atoms on the LHS. We hence, add a co-effecient 2 beside $FeSO_4$ .

2. Now, Iron atoms, Sulphur Atoms and Oxygen atoms occur 2, 2, 8 respectively on both the sides:

Hence, As all the other elements as well as iron, balance, we've arrived upon our Balanced Equation :

$2FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3$

b) We know that, decomposition reactions are [generally] endothermic reactions in which Large Compounds decompose into smaller elements and compounds. Here, as Ferrous Sulphate decomposes into Sulphur Dioxide, Sulphur Trioxide and Ferric Oxide, the reaction that occurs here is Decomposition Reaction.

7 0

2 years ago

Suppose you have 1000 lb of waste copper (II) oxide sitting in the basement of your factory. Do you see a problem with sending i

Free_Kalibri [48]

Answer:

Yes.

Explanation:

Yes, we have a problem with sending it to a landfill of copper oxide because it has harmful effect on the health of humans as well as more weight of the copper oxide. Copper oxide usually found in powder form which can easily be inhaled that causes death of the cell due to toxic effect on the mitochondria and lysosomes of the cell. It makes problem of health in carrying the copper oxide from the basement of the factory to the landfill region due to its power form so we can say that it can do problems to human health while carrying from one place to another.

8 0

2 years ago

A 1.00 L flask is filled with 1.15 g of argon at 25 ∘C. A sample of ethane vapor is added to the same flask until the total pres

tatiyna

Answer:

The partial pressure of argon in the flask = 71.326 K pa

Explanation:

Volume off the flask = 0.001 $m^{3}$

Mass of the gas = 1.15 gm = 0.00115 kg

Temperature = 25 ° c = 298 K

Gas constant for Argon R = 208.13 $\frac{J}{kg k}$

From ideal gas equation P V = m RT

⇒ P = $\frac{m R T}{V}$

Put all the values in above formula we get

⇒ P = $\frac{0.00115}{0.001}$ × 208.13 × 298

⇒ P = 71.326 K pa

Therefore, the partial pressure of argon in the flask = 71.326 K pa

4 0

3 years ago

What would happen to the volume of the container if the pressure is increased by a factor of 2

telo118 [61]

Answer:

volume of the container will decreases if pressure increases.

Explanation:

According to Boyle's law:

Pressure is inversely proportional to volume which means if pressure of a gas increases the volume of the gas will decreases as gas molecules will collide and come closer forcefully so volume will decreases. And its formula for determining volume and pressure is:

PV=nRT

where "R" is a ideal gas constant

"T" is temperature and

"n" is number of particles given in moles while "V" is volume and "P" is pressure.

8 0

2 years ago