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Aleksandr [31]
3 years ago
5

Compare and contrast the goals of the General Mining Law of 1872 and the proposed Hardrock Mining and Reclamation Act of 2009.

Chemistry
1 answer:
Ad libitum [116K]3 years ago
4 0

Answer: seen below

Explanation:

the goals of the General Mining Law of 1872 state that, anyone can stake mining claims on federal land, and they pay no more than $5 an acre while they keep 100% of profits with little to no environmental provisions.

Taxpayers pay for clean up of sites.

While the goals of proposed Hardrock Mining and Reclamation Act of 2009 includes, Increasing acreage of lands off limits to exploration and development. Protecting of National Parks and National Monuments is essential. Giving land managers the ability to balance mineral activities with other uses of public land. Giving state, local and tribal government the ability to put lands off limits to mining although, this bill never became law.

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You want to minimize an objects thermal energy loss on a cold day. How does heat energy transfer affect thermal energy loss?
san4es73 [151]

Answer:

4- A material that transfers heat energy more easily than another material will experience a greater rate of thermal energy loss than an object that does not transfer heat energy easily.

Explanation:

Thermal energy loss has to do with loss of heat energy by a body to another body or its environment. The aim of the process is usually the attainment of thermal equilibrium between the body and its environment.

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3 years ago
The radius of a lithium atom is 130 picometers, and the radius of a fluorine atom is 60 picometers. The radius of a lithium ion,
natali 33 [55]

Answer:

A positive ions is always smaller than the corresponding atom.

A negative ion is always larger than the corresponding atom.

Explanation:

The reason for this is that, when a positive ion is formed, a full shell is usually removed with its electrons thereby reducing the size of the electron cloud and decreasing the size of the electron cloud.

A negative ion is formed by addition of more electrons to the electron cloud hence it spreads out. Interelectronic repulsion accounts for the larger size of the negative ion.

3 0
3 years ago
Calculate the standard enthalpy change for the reaction at 25 ∘ C. Standard enthalpy of formation values can be found in this li
Anastasy [175]

Answer:

-179.06 kJ

Explanation:

Let's consider the following balanced reaction.

HCl(g) + NaOH(s) ⟶ NaCl(s) + H₂O(l)

We can calculate the standard enthalpy change for the reaction (ΔH°r) using the following expression.

ΔH°r = 1 mol × ΔH°f(NaCl(s)) + 1 mol × ΔH°f(H₂O(l)) - 1 mol × ΔH°f(HCl(g)) - 1 mol × ΔH°f(NaOH(s))

ΔH°r = 1 mol × (-411.15 kJ/mol) + 1 mol × (-285.83 kJ/mol) - 1 mol × (-92.31 kJ/mol) - 1 mol × (-425.61 kJ/mol)

ΔH°r = -179.06 kJ

7 0
3 years ago
The volume of 2.050 M copper(II) nitrate that must be diluted with water to prepare 750.0 mL of a 0.8543 M solution is equal to
Lubov Fominskaja [6]

Answer:

.

.

Explanation:

´.

8 0
3 years ago
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