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4 years ago

Compare and contrast the goals of the General Mining Law of 1872 and the proposed Hardrock Mining and Reclamation Act of 2009.

Chemistry

1 answer:

Ad libitum [116K]4 years ago

4 0

Answer: seen below

Explanation:

the goals of the General Mining Law of 1872 state that, anyone can stake mining claims on federal land, and they pay no more than $5 an acre while they keep 100% of profits with little to no environmental provisions.

Taxpayers pay for clean up of sites.

While the goals of proposed Hardrock Mining and Reclamation Act of 2009 includes, Increasing acreage of lands off limits to exploration and development. Protecting of National Parks and National Monuments is essential. Giving land managers the ability to balance mineral activities with other uses of public land. Giving state, local and tribal government the ability to put lands off limits to mining although, this bill never became law.

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What is the density of chlorine gas (MM = 71.0glmol) at 1.50 atm and 25.0C

IrinaVladis [17]

Answer: D=4.35g/L

Explanation:

The formula for density is $D=\frac{M}{V}$ . M is mass in grams and V is volume in liters.

Since we are give pressure and temperature, we can use the ideal gas law to find moles/volume. FInding moles/volume would give us the base for density. All we would have to do is convert moles to grams.

Ideal Gas Law: PV=nRT

$\frac{n}{V} =\frac{P}{RT}$

$\frac{n}{V}=\frac{1.50 atm}{(0.08206Latm/Kmol)(25+274.15K)}$

$\frac{n}{V} =\frac{0.061309mol}{L}$

Now that we have moles, we can use molar mass of chlorine gas to find grams.

$0.061309mol*\frac{71.0g}{mol} =4.3529g$

With our grams, we can find our density.

$D=\frac{4.3529g}{L}$

We need correct significant figures so our density is:

$D=\frac{4.35g}{L}$

5 0

4 years ago

If the concentration of a sugar solution is lower outside the cell than inside the cell which will happen by osmosis?. A.Sugar w

lys-0071 [83]

Answer: option C.Water will move into the cell

Explanation:

1) Start by analyzing what the statement means in terms of relative concentrations:

------------------------ | inside the cell ------------ | outside the cell |

sugar --------------- | higher ----------------------- | lower ------------- |

water -------------- | lower ------------------------- | higher ------------ |

2) Osmosis is the process where a barrier (the celll membrane) permits the pass of some component and not others.

The component that can pass is that whose particles are smaller. Sugar molecules (the solute) are bigger than water molecules (the solvent), so sugar molecules cannot pass the cell membrane. Only water can.

3) The driviing force for the motion of water molecules is called diffusion. The diffusion occurs from higher concentrations to lower concentrations.

Hence, the water molecules will from outside the outiside the cell, where they have the greater concentration, toward the inside of the cell, where water hasa the lower concentration.

As result, the water will move into the cell, which is the option C.

3 0

3 years ago

The oxidation state of phosphorus is +3 in

IgorC [24]

Answer:

b) Phosphorus acid

Explanation:

To distinguish the type of acid of phosphorus with the oxidation state of +3, we need to be familiar with the chemical formula of each of the compounds:

Orthophosphoric acid H₃PO₄

Phosphorus acid H₃PO₃

Metaphosphoric acid HPO₃

Phyrophosphoric acid H₄P₂O₇

Now that we know the formula of the given compounds, the algebraic sum of all the oxidation numbers of all atoms in a neutral compound is zero:

Only phosphorus acid yielded an oxidation state of +3 for phosphorus in the compound.

H₃PO₃:

we know the oxidation state of H = +1

O = -2

The oxidation state of P is unknown. We can express this as an equation:

3(+1) + P + 3(-2) = 0

3 + P -6 = 0