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KiRa [710]
3 years ago
12

Pls explain ionization energy​

Chemistry
1 answer:
Oliga [24]3 years ago
4 0

Answer:the energy required by an atom to lose or gain electron (e-) to be able to form ions.either cation or anion.

Explanation:

to lose or gain e- an atom has to donate or receive e- to to this it requires the more easily it can lose an electron the more electro positive it is and the more easily it gains electron the more electro negative it is.

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What is the percent composition of aluminum in the ore bauxite (AI2O3)?
Schach [20]

Answer:

Molar mass of Al2O3 = 101.961276 g/mol

This compound is also known as Aluminium Oxide.

Convert grams Al2O3 to moles or moles Al2O3 to grams

Molecular weight calculation:

26.981538*2 + 15.9994*3

Percent composition by element

Element Symbol Atomic Mass # of Atoms Mass Percent

Aluminium Al 26.981538 2 52.925%

Oxygen O 15.9994 3 47.075%

Explanation:

Percent composition by element

Element Symbol Mass Percent

Aluminium Al 52.925%

Oxygen O 47.075%

6 0
3 years ago
What is the mass of a sample of NH3 containing 7.20 x 10^24 molecules of NH3?
leva [86]

Answer:203

Explanation: just have to timez

4 0
3 years ago
J5 protons and 74 electrons
Brrunno [24]

Answer:

ins the same

Explanation:

neutrons have no charge

8 0
3 years ago
Salt is an ionic compound that is produced when a cation and an anion from an acid-base reaction combine, and solutions of salts
Andrej [43]

Answer:

a. True

Explanation:

The statement given regarding salt is correct,

Salt is ionic in nature, as it is composed of a positive ion, i.e. , cation and a negative ion, i.e. , anion.

Salt can be made by the combination of respective acid and base.

There are three nature of salt, acid, base and neutral.

Hence, from the given statement of the question,

The correct option is a. True.

3 0
3 years ago
If the freezing point of an aqueous 0.10 m glucose solution is −x°c, what is the approximate freezing point of a 0.10 m nacl sol
maks197457 [2]
Answer is: the approximate freezing point of a 0.10 m NaCl solution is -2x°C.
V<span>an't Hoff factor (i) for NaCl solution is approximately 2.
</span>Van't Hoff factor (i) for glucose solution is 1.<span>
Change in freezing point from pure solvent to solution: ΔT = i · Kf · m.
Kf - molal freezing-point depression constant for water is 1,86°C/m.
m -  molality, moles of solute per kilogram of solvent.
</span>Kf and molality for this two solutions are the same, but Van't Hoff factor for sodium chloride is twice bigger, so freezing point is twice bigger.
8 0
3 years ago
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