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Schach [20]
3 years ago
6

The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is its greatest possible v

alue for width?
Mathematics
2 answers:
Nana76 [90]3 years ago
7 0

Answer:

Step-by-step explanation:

Perimeter= 2L+2W. If L=3W(three times the width) then 2(3W)+2W=112. Or 6W+2W=112 which is equal to 8W=112. To solve for the width, divide both sides by 8 and find 112/8=14, therefore W=14.

lisabon 2012 [21]3 years ago
5 0

Answer:

14 cm

Step-by-step explanation:

Given the length is 3 times the width

If each width is denoted by W, then each length is L = 3W

Perimeter (add up all lengths and widths),

= L + L + W + W

= 3W + 3W + W + W

= 8W

Given that the max perimeter is 112cm

hence 8W = 112,

W = 14 cm at most

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Number 2 i need help
daser333 [38]
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-- Make a second column, next to the 6 and 7.  This column will be
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-- You know that there are 42 marbles, so write '42' in the box
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Ask yourself: "  Self !  What does the 6 have to be multiplied with to get 42 ?" 

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6 0
3 years ago
Complete the pattern 4,15,7,12,10,9 ? ? ? show me how you got your work
kkurt [141]
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6 0
3 years ago
Read 2 more answers
I don’t understand this.
alexira [117]
I’ll solve number 3.

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So, in conclusion, n = 4.

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8 0
3 years ago
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