The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is its greatest possible v alue for width?
2 answers:
Answer:
Step-by-step explanation:
Perimeter= 2L+2W. If L=3W(three times the width) then 2(3W)+2W=112. Or 6W+2W=112 which is equal to 8W=112. To solve for the width, divide both sides by 8 and find 112/8=14, therefore W=14.
Answer:
14 cm
Step-by-step explanation:
Given the length is 3 times the width
If each width is denoted by W, then each length is L = 3W
Perimeter (add up all lengths and widths),
= L + L + W + W
= 3W + 3W + W + W
= 8W
Given that the max perimeter is 112cm
hence 8W = 112,
W = 14 cm at most
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