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4 years ago

a bomber is flying horizontally at a speed of 800.0 ft/s and an altitude of 1000.0 ft when it is drops a bomb

Physics

1 answer:

patriot [66]4 years ago

7 0

Answer:

The range, S = 6307.82 ft

Explanation:

Given,

The horizontal velocity of the bomber, Vx = 800 ft/s

The altitude of the bomber, h = 1000 ft

The range of the projectile is given by the relation

If the vertical component of the velocity is zero, the equation becomes

S = Vx √(2gh) / g

Substituting the given values,

S = 800 √(2X 32.17 X 1000) / 32.17

= 6307.82 ft

Hence, the bomb falls at a distance, S = 6307.82 ft

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3 years ago

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4 years ago

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Answer:

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first mass, m1

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