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3 years ago

Is the formular of preasure P=F÷A

Physics

2 answers:

Stels [109]3 years ago

8 0

Answer:

yes the formula of pressure is P = F/A

laiz [17]3 years ago

3 0

Answer:

yes it is

Explanation:

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By what factor must the amplitude of a sound wave be decreased in order to decrease the intensity by a factor of 3?

s344n2d4d5 [400]

Answer:

Amplitude is decreased by a factor of $\sqrt3$ if intensity is decreased by a factor of 3.

Explanation:

Intensity of a sound wave is directly proportional to the square of its amplitude.

Therefore, if intensity is $I$ and amplitude is $A$ , then

$I=kA^2$ , where, $k$ is constant of proportionality.

Now, if intensity of sound wave is decreased by a factor of 3. So,

New intensity is, $I_{new}=\frac{I}{3}$

$I_{new}=kA_{new}^2\\\frac{I}{3}=kA_{new}^2$

Plug in $kA^2$ for $I$ . This gives,

$\frac{kA^2}{3}=kA_{new}^2\\A_{new}^2=\frac{A^2}{3}\\A_{new}=\sqrt{\frac{A^2}{3}}=\frac{A}{\sqrt{3}}$

Therefore, amplitude is decreased by a factor of $\sqrt3$ .

4 0

3 years ago

An attack helicopter is equipped with a 20- mm cannon that fires 88.7 g shells in the forward direction with a muzzle speed of 9

Svetradugi [14.3K]

The impulse imparted to the shells equals the change in the momentum:
Fav*(Delta t)= Delta m*v.
The mass change is
Delta m= n*m= (89.9shells)*(88.7g)=7.97Kg
So the average force is
F=((v)*(Delta m))/t= ((929)*(7.97))/4.84=1529.78 N
Since the velocity of the shells is much greater than the velocity of the helicopter, there is no need to use relative velocity.

4 0

3 years ago

In an old-fashioned amusement park ride, passengers stand inside a 3.0-m-tall, 5.0-m-diameter hollow steel cylinder with their b

lesya692 [45]

Answer:2.55 rad/s

Explanation:

Given

Diameter of ride=5 m

radius(r)=2.5 m

Static friction coefficient range=0.60-1

Here Frictional force will balance weight

And limiting frictional force is provided by Centripetal force

$f=\mu N=\mu m\omega ^2\cdot r$

weight of object=mg

Equating two

f=mg

$\mu m\omega ^2\cdot r=mg$

$\omega ^2=\frac{g}{\mu r}$

$\omega =\sqrt{\frac{g}{\mu r}}$

$\omega =2.55 rad/sec$

8 0

3 years ago

Convert 14 mg to kg ....

____ [38]

<h2>♨ANSWER♥</h2>

14mg = 14 × 10^-3 g

= 14 × 10^-3 / 10^3 kg

= 14 × 10^-6 kg

= 0.014 kg

☆...hope this helps...☆

_♡_mashi_♡_

7 0

2 years ago

Read 2 more answers

What volume of lead must be fastened underneath it to sink the wood in calm water so that its top is just even with the water le

astraxan [27]

The bouyancy force is:

Since the wood-lead system is completely submerged, the bouyancy force

is FB = ĎwgVl + ĎwgVb, where Ďw is the density of water,Vl

is the volume of

the piece of lead and Vb is the volume of the wooden block. The weight of the

  combined lead and wooden block is: W = ĎlgVl + ĎbgVb. Since the system is

in equilibrium, the bouyancy force must be equal to the total weight:

ĎwgVl + ĎwgVb = ĎlgVl + ĎbgVb

now we can solve for the volume of lead:

ĎwgVl â’ ĎlgVl = ĎbgVb â’ ĎwgVb

Vl(Ďw â’ Ďl) = Vb(Ďb â’ Ďw)

Vl =

Ďbâ’Ďw

Ďwâ’Ďl

Vb

Now we substitute the values for the density of lead Ďl = 11.3 Ă— 103kg/m3  ,

the density of the wood and the density of water Ďw = 1000kg/m3

. We get:

Vl =

600â’1000

1000â’11300

(0.6m Ă— 0.25m Ă— 0.08m) = 4.66 Ă— 10â’4m3

4 0

3 years ago

Is the formular of preasure P=F÷A​

Is the formular of preasure P=F÷A