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HACTEHA [7]
3 years ago
12

On the planet Xenophous a 1.00 m long pendulum on a clock has a period of 1.32 s. What is the free fall acceleration on Xenophou

s?
Physics
1 answer:
myrzilka [38]3 years ago
8 0
The period of the pendulum is given by the following equation

T = 2<span>π * sqrt (L/g)

Where g is the gravity (free fall acceleration)

L is the longitude of the pendulum

T is the period.

We find g.............> (T /2</span>π)<span>^</span><span>2 = L/g

g = L/(</span>T /2π)^2...........> g = 22.657 m/s^2
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True or false. electrons move in orbits in the same way plants orbit the sun
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One plants don't orbit the sun, the earth does.
two true if its saying plants orbit the sun
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3 years ago
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A cyclist rides at 6.20 m/s through a intersection. A stationary car begins to
Xelga [282]

Answer:

The width of the intersection is 20 meters

Explanation:

The speed with which the cyclist is riding, v₁ = 6.20 m/s

The rate at which the car starts to accelerate, a = 3.844 m/s²

The initial velocity of the car = The car is stationary at the start = 0 m/s

The time at which the cyclist and the car reach the other side of the intersection = The same time;

Let 't' represent the time at which the cyclist and the car both reach the other side of the intersection, we have;

The distance travelled by the cyclist = The distance traveled by the car

∴ v₁ × t = 1/2 × a × t²

Plugging in the values for 'v₁', and 'a' in the above equation, we get;

6.20 × t = 1/2 × 3.844 × t²

∴ 1.922·t² - 6.20·t = 0

∴ t·(1.922·t - 6.20) = 0

t = 0, or t = 6.20/1.922 = 100/31

The time at which the cyclist and the car both reach the other side of the intersection, t = 100/31 seconds

The with of the intersection, w = v₁ × t

∴ w = 6.20 × 100/31 = 100/5 = 20

The width of the intersection, w = 20 meters.

8 0
3 years ago
Based on Kepler's work, which best describes the orbit If a planet around the Sun?
krek1111 [17]

Answer:

an ellipse with the Sun at one focus  or D

Explanation:

Answer for edgenuity

7 0
3 years ago
Solenoid 2 has twice the radius and six times the number of turns per unit length as solenoid 1. The ratio of the magnetic field
Xelga [282]

Answer:

6

Explanation:

The magnetic field inside a solenoid is given by the following formula:

B = \mu_{0}nI

where,

B = Magnetic Field Inside Solenoid

μ₀ = permittivity of free space

n = No. of turns per unit length

I = Current Passing through Solenoid

For Solenoid 1:

B_{1} = \mu_{0}n_{1}I  ------------------- equation 1

For Solenoid 2:

n₂ = 6n₁

Therefore,

B_{1} = \mu_{0}n_{2}I\\B_{1} = 6\mu_{0}n_{1}I  ----------------- equation 2

Diving equation 1 and equation 2:

\frac{B_{2}}{B_{1}} = \frac{6\mu_{0}nI}{\mu_{0}nI}\\\\\frac{B_{2}}{B_{1}} = 6

Hence, the correct option is:

<u>6</u>

8 0
2 years ago
A boy is exerting a force of 70 N at a 50-degree angle on a lawn mower. He is accelerating at 1.8 m/s2. Round the answers to the
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25 kg and 299N are the answers
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