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2 years ago

* THE ANSWER IS D * Silicon (chemical symbol Si) is located in Group 14, Period 3. Which is silicon most likely

Physics

2 answers:

laila [671]2 years ago

8 0

Answer:

D. Metalloid with properties of both metals and nonmetals

o-na [289]2 years ago

4 0

Answer:

Hank u so much out don't know how much this rally

Explanation:

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8-30-2018 what phase change occurs as the substance at 0 degree c has its pressure dropped from 0.50 at to 0.25 atm

madam [21]

Answer:

at T = 0ºC the change of state is from the solid state to the gaseous state

Explanation:

In this exercise we are asked about the changes of state, from the data we will assume that the material is water.

Water can exist in three solid states, liquid and gas, in a graph of pressure ℗ against temperature (T) there is a point called triple at T = 0.01ºC, below this point the curve has two states at high pressure solid and low pressure gas.

As a result of the previous ones at T = 0ºC the change of state is from the solid state to the gaseous state

7 0

2 years ago

PLEASE HELP! I'LL GIVE BRAINLEST

erma4kov [3.2K]

Answer:

8.162

Explanation:

W=mg

= 2.2 x 3.71

= 8.162 N

5 0

2 years ago

You connected the 5 Ω, 10 Ω, 15 Ω resistors in series with a 90 V battery. What is the current?

kykrilka [37]

Answer:

Explanation:

Rtoal=R1+R2+R3=5+10+15=30

I=V/R 90/30

I=3

3 0

2 years ago

The kinetic energy of a proton and that of an a-particle are 4 eV and 1 eV,

madam [21]

Answer:

(b) 1:1

Explanation:

1. Formulae:

E = hf

E = h.v/λ

λ = h/(mv)

E = (1/2)mv²

Where:

E = kinetic energy of the particle
λ = de-Broglie wavelength
m = mass of the particle
v = speed of the particle
h = Planck constant

2. Reasoning

An alha particle contains 2 neutrons and 2 protons, thus its mass number is 4.

A proton has mass number 1.

Thus, the relative masses of an alpha particle and a proton are:

$\dfrac{m_\alpha}{m_p}=4$

For the kinetic energies you find:

$\dfrac{E_\alpha}{E_p}=\dfrac{m_\alpha \times v_\alpha^2}{m_p\times v_p^2}$

$\dfrac{1eV}{4eV}=\dfrac{4\times v_\alpha^2}{1\times v_p^2}\\\\\\\dfrac{v_p^2}{v_\alpha^2}=16\\\\\\\dfrac{v_p}{v_\alpha}=4$

Thus:

$\dfrac{m_\alpha}{m_p}=4=\dfrac{v_p}{v__\alpha}$

$m_\alpha v_\alpha=m_pv_p$

From de-Broglie equation, λ = h/(mv)

$\dfrac{\lambda_p}{\lambda_\alpha}=\dfrac{m_\lambda v_\lambda}{m_pv_p}=\dfrac{1}{1}=1:1$

5 0

3 years ago

In an emergency situation, firemen need to respond as quickly as possible. If a fireman is responding from the second floor, how

rjkz [21]

Answer:

4m/s

Explanation:

May be different considering how long the pole is and how heavy the firefighter is.

8 0

2 years ago