3 years ago

2,3,5,6. Only plz and thank u

Mathematics

1 answer:

vfiekz [6]3 years ago

3 0

For 3, it is an isosceles triangle and it is an acute triangle.

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What is the following sum 3b^2

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This can be simplified as :

= $3*b^2*(\sqrt[3]{27 *2*a}) + 3*(\sqrt[3]{2*a*b^6})$

We know that: $\sqrt[3]{27} = 3$

Similarly we also can simplify: $\sqrt[3]{b^6} = b^2$

So our expression will look like this:

= $3*3*b^2*(\sqrt[3]{2a}) + 3*b^2*(\sqrt[3]{2a})$

= $9b^2*(\sqrt[3]{2a}) + 3b^2*(\sqrt[3]{2a})$

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This can also be written as:

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