Answer:
c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
Thus, the rate is given as:
It is necessary to remember that each concentration to time interval is divided into the stoichiometric coefficient, that is why HBr has a 1/2. Moreover, the concentration HBr is negative since it is a reactant and it has a negative rate due to its consumption.
Therefore, the answer is:
c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt
Best regards.
<h3>Answer:</h3>
Mass = 96.47 g
<h3>
Solution:</h3>
Data Given:
M.Mass = 28.97 g.mol⁻¹
Moles = 3.33 mol
Mass = ??
Formula Used:
Moles = Mass ÷ M.Mass
Solving for Mass,
Mass = Moles × M.Mass
Putting values,
Mass = 3.33 mol × 28.97 g.mol⁻¹
Mass = 96.4701 g
Rounding to four significant numbers,
Mass = 96.47 g
Answer:
D. a solution made by mixing 100 mL of 0.100 M CH3COOH and 50 mL of 0.100 M NaOH
Explanation:
Buffer solutions are the solutions which can resist the change in the pH up to some extent.
The pH of a buffer solution can be measured by the equation known as Henderson–Hasselbalch equation.
pH=pKa+log[base]/[acid]
Buffer solutions are the solutions of either weak acid and conjugate base of it or weak base and conjugate acid of it.
Hence, a weak acid and a strong base can result in weak acid and it's conjugate and can acts as a buffer.
Option D is correct.
Answer:
water evaporate from surfaces
Explanation:
after it clumps to air to make clouds ,cools turn to liquid and rains or precipitate and becomes runoff
Alright sounds good and also thank you so much for the free points dawg