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Sergeu [11.5K]
3 years ago
6

At stp how many liters of nh3 can be produced from the reaction of 6.00 mol of n2 with 6.00 mol of h2?

Chemistry
1 answer:
svp [43]3 years ago
3 0
3H2+N2→2NH3
here h2 H2 is limiting reagent
6moles of H2 will give 4moles of NH3
V of NH3 produced=22.4*4L
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Convert 15.6 g Na2Cr2O7 to moles of Na2Cr2O7.
Leviafan [203]

Answer:

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Explanation:

3 0
3 years ago
Consider the chemical equations shown here.
vichka [17]

P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

Explanation:

The overall equation for the reaction that produces  P₄0₁₀ is :

P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

Now let us derive this equation:

Given equations:

   P₄_{s} + 30₂_{g}  ⇒ P₄0₆_{s}  equation 1;

   P₄_{s} + 50₂_{g} ⇒  P₄0₁₀_{s}  equation 2;

To get the overall combined equation, the equation 1 must be reversed and added to equation 2:

            P₄0₆_{s} ⇒ P₄_{s} + 30₂_{g}   equation 3

                      +

            equation 2:

 P₄_{s} + 50₂_{g}  +    P₄0₆_{s}  ⇒  P₄0₁₀_{s}  +  P₄_{s} + 30₂_{g}  

cancelling specie that appears on both sides and removing excess oxygen gas on the reactant side gives;

   

                  P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

learn more:

Net equation brainly.com/question/2947744

#learnwithBrainly

5 0
3 years ago
At the candy store, gourmet jelly beans sell for $1.15 per ounce. There are 28 students in Alfred's class. If each student eats
saw5 [17]

Answer:

Total cost = $40.25 (Approx)

Explanation:

Given:

Per ounce = $1.15

Number of student = 28

Each student eat = 0.035 kg

Find:

Total cost

Computation:

Total weight of candy = 28 × 0.035 kg

Total weight of candy = 0.98 kg

1 ounce = 0.028 kg (approx).

Total weight of candy = 0.98 kg / 0.028

Total weight of candy = 35 ounce (Approx)

Total cost = 35 × $1.15

Total cost = $40.25 (Approx)

8 0
3 years ago
What is molarity?explain with example​​
larisa [96]

Answer:

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prank hahahaha

Explanation:

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6 0
2 years ago
The diagram illustrates the water cycle.
Amiraneli [1.4K]

Answer:

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Explanation:

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3 0
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