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Nookie1986 [14]
3 years ago
9

How can water be changed into ice​

Chemistry
1 answer:
tankabanditka [31]3 years ago
3 0

Answer:

- The molecules stick together and form a solid making ice

- By removing heat

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Part A
algol13
The correct answer for the question that is being presented above is this one: "C) The reaction is spontaneous at high temperatures." 
Since dH is positive and dS ~ 0 then -TdS ~ 0, meaning dG will always be greater than 0 so t<span>he reaction is spontaneous at high temperatures.</span>
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3 years ago
How are the ion and isotope different from the atom?
puteri [66]
Ions have an extra or lost an electron. Isotopes have different numbers of neutrons.
7 0
3 years ago
Prepare 10.00 mL of 0.010 M NaOH by diluting the NaOH solution used in Trial 1. (Your procedure should clearly show your calcula
denis-greek [22]

Answer:

<em> = 0.2 mL.</em>

Explanation:

Given a 0.5 M solution of NaOH as stock solution, 10.0mL of 0.010M can be prepared via dilution with distilled water, by using the formula:

C_{1} V_{1} = C_{2} V_{2}

where C1 and V1 are initial concentration and volume respectively; same as C2 & V2 for fina.

Let C1 = 0.5M, V2 = ?

C2 = 0.010M; V2 = 10mL

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= \frac{10}{0.5} × 0.010

<em> = 0.2 mL.</em>

Glasswares used would be pipette (for smaller volume experiment) and measuring cylinder. 0.2mL would be measured and then made upto the 10mL mark of the measuring cylinder.

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3 0
3 years ago
Which describes the polarity in a water molecule?
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7 0
3 years ago
Read 2 more answers
1. A 25 g rock is placed in a graduated cylinder with water. The volume of the liquid rises from 18.3 mL to 21.4 mL Calculate th
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Answer:

1. \rho=8.06g/cm^3

2. H=10cm

Explanation:

Hello,

1. In this case, since the volume of the rock is obtained via the difference between the volume of the cylinder with the water and the rock and the volume of the cylinder with the water only:

V=21.4mL-18.3mL=3.1mL

Thus, the density turns out:

\rho=\frac{m}{V}=\frac{25g}{3.1cm^3}  \\\\\rho=8.06g/cm^3

2. In this case, given the density and mass of aluminum we can compute its volume as follows:

V=\frac{m}{\rho}=\frac{1080g}{2.7g/cm^3}=400cm^3

Moreover, as the volume is also defined in terms of width, height and length:

V=W*H*L

The height is computed to be:

H=\frac{V}{L*W}=\frac{400cm^3}{5cm*8cm}\\ \\H=10cm

Best regards.

3 0
3 years ago
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