Answer:
24.9mL of the stock solution are required
Explanation:
To solve this question we have to find, as first, the moles of HCl that we need to prepare the desire solution. These moles are taken from the stock solution as follows:
<em>Moles diluted solution:</em>
500.0mL = 0.5000L * (0.613mol / L) = 0.3065 moles HCl
As these moles comes from the 12.3M HCl solution, the volume that we need of the stock solution is:
<em>Volume stock solution:</em>
0.3065 moles HCl * (1L / 12.3moles) = 0.0249L 12.3M HCl =
<h3>24.9mL of the stock solution are required</h3>
Answer:
TABLE OF CONJUGATE ACID-BASE PAIRS Acid BaseK a (25oC) HClO 4ClO 4 – H 2 SO 4HSO 4 – HCl Cl– HNO 3NO 3 – H 3 O +H 2 O H 2 CrO 4HCrO 4 –1.8 x 10–1
Explanation:
