Determine the volume (L) of nitrogen monoxide gas that is created at STP when 32.2 g

For the equilibrium

Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

$H_2S=0.596M$

$H_2=0.004 M$

$S_2=0.002 M$

Explanation:

We are given that for the equilibrium

$2H_2S\rightleftharpoons 2H_2(g)+S_2(g)$

$k_c=9.0\times 10^{-8}$

Temperature, $T=700^{\circ}C$

Initial concentration of

$H_2S=0.30M$

$H_2=0.30 M$

$S_2=0.150 M$

We have to find the equilibrium concentration of gases.

After certain time

2x number of moles of reactant reduced and form product

Concentration of

$H_2S=0.30+2x$

$H_2=0.30-2x$

$S_2=0.150-x$

At equilibrium

Equilibrium constant

$K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}$

Substitute the values

$9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}$

By solving we get

$x\approx 0.148$

Now, equilibrium concentration of gases

$H_2S=0.30+2(0.148)=0.596M$

$H_2=0.30-2(0.148)=0.004 M$

$S_2=0.150-0.148=0.002 M$

3 0

3 years ago

A compound has a percent composition of 54.5% carbon, 9.3% hydrogen and 36.2 % oxygen.If its molar mass is 88 g/mol, what is its

drek231 [11]

Answer:

C₄H₈O₂.

Explanation:

Firstly, we can calculate the no. of moles (n) of each component using the relation:

n = mass/atomic mass,

mol C = mass/(atomic mass) = (54.5 g)/(12.0 g/mol) = 4.54 mol.

mol H = mass/(atomic mass) = (9.3 g)/(1.0 g/mol) = 9.3 mol.

mol O = mass/(atomic mass) = (36.2 g)/(16.0 g/mol) = 2.26 mol.

To get the empirical formula, we divide by the lowest no. of moles (2.26 mol) of O:

∴ C: H: O = (4.54 mol/2.26 mol) : (9.3 mol/2.26 mol) : (2.26 mol/2.26 mol) = 2: 4: 1.

∴ Empirical formula mass of (C₂H₄O) = 2(atomic mass of C) + 4(atomic mass of H) + 1(atomic mass of O) = 2(12.0 g/mol) + 4(1.0 g/mol) + (16.0 g/mol) = 44.0 g/mol.

∴ Number of times empirical mass goes into molecular mass = (88.0 g/mol)/(44.0 g/mol) = 2.0 times.

∴ The molecular formula is, 2(C₂H₄O), that is; (C₄H₈O₂)

4 0

3 years ago

Na3PO4 + AlBr3 ----> ?

Sati [7]

Na₃PO₄(aq)+AlBr₃(aq)→3NaBr(aq)+AlPO₄(s)

This is a double replacement reaction. You can tell that there has to be 3NaBr molecules since there are 3 Na atoms in sodium phosphate and 3 Br atoms in aluminum bromide. We also know that Na has an oxidation number of +1 which means PO₄ needs to have an oxidation number of -3 while Br has an oxidation number of -1 which means Al has an oxidation number of +3. That means that Al³⁺ and PO₄³⁻ can from AlPO₄
I hope this helps. Let me know if anything is unclear.

8 0

4 years ago

What shape has the largest area to perimeter ratio.

antiseptic1488 [7]

Circle-Thus a circle has the largest area of any closed figure with a given perimeter

8 0

3 years ago

What particle is emitted when lead-214, 214 82 pb undergoes natural radioactive decay to bismuth-214, 214 83 bi?

const2013 [10]

A beta particle.β
 Looking at the particles before and after for the decay, you'll see that there is a total of 214 neutrons and protons both before and after the radioactive decay. But you'll also see that before the decay, there were 82 protons and after the decay, there are 83 protons. So a neutron was converted to a proton which means that a negative charge had to be emitted, so it's a beta decay where a neutron emits a beta particle (an electron). The beta particle can be represented as a greek beta β followed by a minus sign, giving β-, or as a "e" followed by a minus sign, so e-

6 0

3 years ago