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Bond [772]
3 years ago
12

Determine the volume (L) of nitrogen monoxide gas that is created at STP when 32.2 g

Chemistry
1 answer:
brilliants [131]3 years ago
8 0

what is it i don't get it means i don't understand

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What is the pH of a solution that is 0.10 M formic acid and 0.0065 M formate (the conjugate base)? Ka of formic acid = 1.77 x 10
Dima020 [189]

Answer:

pH = 2.56

Explanation:

The Henderson-Hasselbalch equation relates the pH to the Ka and ratio of the conjugate acid-base pair as follows:

pH = pKa + log([A⁻]/[HA]) = -log(Ka) + log([A⁻]/[HA])

Substituting in the value gives:

pH = -log(1.77 x 10⁻⁴) + log((0.0065M) / (0.10M))

pH = 2.56

3 0
3 years ago
PLEASE HELP!! thank you Which element does X represent?
jarptica [38.1K]

Answer:

95 Kr36

Explanation:

The process by which a large nucleus split into two smaller nuclei is called nuclear fission and occurs after the nucleus has absorbed a neutron that is a product of the radioactive decay of another atom. The formed fission fragments are unstable and extremely radioactive.

8 0
3 years ago
If 13.7 grams of manganese oxide reacts with excess hydrogen chloride gas, how many grams of water are formed?
Lerok [7]

Answer:

5.67 g OF WATER WILL BE FORMED WHEN 13.7 g OF MnO2 REACTS WITH HCl GAS.

Explanation:

EQUATION FOR THE REACTION

Mn02 + 4HCl --------> MnCl2 + Cl2 + 2H2O

From the balanced reaction between manganese oxide and hydrogen chloride gas;

1 mole of MnO2 reacts to form 2 mole of water

At STP, the molecular mass of the sample is equal to the mole of the substance. So therefore:

(55 + 16 * 2) g of MnO2 reacts to form 2 * ( 1 *2 + 16) g of water

(55 + 32) g of MnO2 reacts to form 2 * 18 g of water

87 g of MnO2 reacts to form 36 g of water

If 13.7 g of MnO2 were to be used?

87 g of MnO2 = 36 g of H2O

13.7 g of MnO2 = ( 13.7 * 36 / 87) g of water

= 493.2 / 87 g of water

Mass of water = 5.669 g of water

Approximately 5.67 g of water will be formed when 13.7 g of manganese oxide reacts with excess hydrogen chloride gas.

3 0
3 years ago
A buffer was prepared by mixing 1.00 mole of ammonia and 1.00 mole of ammonium chloride to form an aqueous solution with a total
lidiya [134]

Answer:

Idek sorry

Explanation:

So sorry i think its 1.00

3 0
3 years ago
What is the formula for this<br> ionic crystal?
mafiozo [28]
69 nice hoemmdmdmdkdjd
3 0
3 years ago
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