Bacteria are smaller than viruses.<br><br>True<br><br>False<br><br>

You have been working to develop a new fictitious compound in the lab. Determine the amount in units of moles [mol] of 40 grams

Serhud [2]

Answer : The moles of given compound is, 0.064 mole

Explanation : Given,

Mass of given compound = 40 g

Atomic mass of X = 50 amu

Atomic mass of Y = 45 amu

Atomic mass of Z = 10 amu

First we have to calculate the molar mass of given compound.

The given compound formula is, $X_5Y_7Z_6$

Molar mass of $X_5Y_7Z_6$ = (5 × Atomic mass of X) + (7 × Atomic mass of Y) + (6 × Atomic mass of Z)

Molar mass of $X_5Y_7Z_6$ = (5 × 50) + (7 × 45) + (6 × 10) = 625 g/mol

Now we have to calculate the moles of given compound.

$\text{Moles of given compound}=\frac{\text{Mass of given compound}}{\text{Molar mass of given compound}}$

$\text{Moles of given compound}=\frac{40g}{625g/mol}$

$\text{Moles of given compound}=0.064mol$

Thus, the moles of given compound is, 0.064 mole

6 0

4 years ago

Calculate the ph at the equivalence point for the titration of 0.230 m methylamine (ch3nh2) with 0.230 m hcl. the kb of methylam

Vlad1618 [11]

Answer: The pH at the equivalence point for the titration will be 0.65.

Solution:

Let the concentration of $[OH^-]$ be x

Initial concentration of $[CH3NH_2]$ , c = 0.230 M

$CH_3NH_2+H_2O\rightleftharpoons CH_3NH_3^++OH^-$

at eq'm c-x x x

Expression of $K_b$ :

$K_b=\frac{[CH_3NH_3^+][+OH^-]}{[CH_3NH_2]}=\frac{x\times x}{c-x}=\frac{x^2}{c-x}$

Since ,methyl-amine is a weak base,c>>x so $c-x\approx c$ .

$K_b=\frac{x^2}{c}=5.0\times 10^{-4}=\frac{x^2}{0.230 M}$

Solving for x, we get:

$x=1.07\times 10^{-2} M$

Given, HCl with 0.230 M , it dissociates fully in water which means $[H^+]$ = 0.230 M

$[OH^-]=[H^+]$ will result in neutral solution, since $[OH^-]$

Remaining $[H^+]$ after neutralizing $[OH^-]$ ions

$[H^+]_{\text{left in solution}}=[H^+]-[OH^-]=0.230-1.07\times 10^{-2}=0.2193 M$

$pH=-log{[H^+]_{\text{left in solution}}=-log(0.2193)=0.65$

The pH at the equivalence point for the titration will be 0.65.

8 0

4 years ago

How many moles are represented by 3.01 - 1023 helium atoms?

Pavlova-9 [17]

Answer:

0.5 mol

Explanation:

Given data:

Number of atoms of He = 3.01 ×10²³

Number of moles = ?

Solution:

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.02 × 10²³ is called Avogadro number.

1 mole = 6.02 × 10²³ atoms

3.01 ×10²³ atoms × 1 mol / 6.02 × 10²³ atoms

0.5 mol

7 0

3 years ago

What is the engine piston displacement in liters of an engine who’s displacement is listed as 430 in.²

sergeinik [125]

For an engine whose displacement is listed as 430 in.², the engine piston displacement in liters is mathematically given as

PD= 7.37 L

<h3>What is the engine piston displacement in liters of an engine whose displacement is listed as 430 in.²?</h3>

Generally, the equation for the dimensional analysis method,\, we convert in to L is mathematically given as

l*(v/l)*l/v

Therefore, piston displacement

PD=(450 in3) . (1 dm3 / 61.024 in3) . (1 L / 1 dm3)

PD= 7.37 L

In conclusion, piston displacement

PD= 7.37 L

Bacteria are smaller than viruses.TrueFalse​

Bacteria are smaller than viruses.TrueFalse