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Vikentia [17]
3 years ago
11

How many grams of ammonia (NH3) are produced in the haber process when using 4.04 g of hydrogen gas?

Chemistry
1 answer:
iren2701 [21]3 years ago
7 0

Answer:

b 204

Explanation:

it is right

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what two variables is acceleration dependent on? what is the relationship between these variables and acceleration?
Citrus2011 [14]
Acceleration (change of movement) of an object is dependent on the net force acting on it and its mass.

The relationship between acceleration (a), force (f) and mass (m) is given by the Second Lay of Newton: f = m * a.

Note that the force, f, is the net force acting on the objetct.

I hope this help you.


8 0
3 years ago
When the number of protons and electrons is the same for an atom, the atom is
lawyer [7]

Answer:

A) Neutral.

Explanation:

Protons are positively charged and electrons are negatively charged, while neutrons have no charge. In a "neutral atom", the number of protons must be equal to the number of electrons, otherwise it would not be neutral.

Hope this helps! :)

8 0
4 years ago
A helium nucleus is formed from hydrogen nuclei. What nuclear change has occured? a.) beta decay b.) none c.) alpha decay d.) nu
Feliz [49]

Answer:

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3 0
3 years ago
HELP - a solution NaOCl was prepared at pH 10.3. calculate the concentration of the salt formed. Given Ka for HOCl=3.0x10^-8
GenaCL600 [577]
First we dissociate the salt

NaOCl ⇒ Na⁺ + OCl⁻
note that [NaOCl] = [OCl⁻]

note that Na⁺ does not undergo hydrolysis so it is a spectator.
OCl⁻ can reform HOCl in an equilibrium, with OCl⁻ acting as the base.

OCl⁻ + H₂O ⇄ OH⁻ + HOCL

<span>Ka for HOCl = 3.0x10^-8, therefore

Kb for OCL</span>⁻ = Kw / (Ka for HOCl)
                       = 1.0 × 10⁻¹⁴ / 3.0 <span>× 10⁻⁸
                       = 3.3 × 10⁻⁷

</span>since Kb for OCl⁻ is given, and the pH is given, then [OCl⁻] must be found, and [OCl⁻] = [NaOCl]

convert the pH into [OH⁻]:
pOH = 14 - pH = 14 - 10.3 = 3.7
[OH⁻] = 10^(-3.7) = 1.995 × 10⁻⁴

set up equib table

          OCl⁻                + H₂O    ⇄      OH⁻        +           HOCl
  ST     x                                               0                             0
 +Δ    -1.995 × 10⁻⁴                   +1.995 × 10⁻⁴        +1.995 × 10⁻⁴
---------------------------------------------------------------------------------
 EQ:   x -1.995 × 10⁻⁴                 1.995 × 10⁻⁴          1.995 × 10⁻⁴

Kb = [OH⁻][HOCl] / [OCl⁻]
3.3 × 10⁻⁷ = (1.995 × 10⁻⁴)² / (x -1.995 × 10⁻⁴ )
x = 1.1963 × 10⁻¹ M = [OCl⁻] = [NaOCl]

The concentration of the salt formed, <span>NaOCl,</span> is 1.2 × 10⁻¹ M

7 0
4 years ago
Sufficient strong acid is added to a solution containing Na2HPO4 to neutralize one-half of it. what will be the pH of this solut
34kurt
The neutralization of the base with an acid will result to the formation of salt and water. In this case, a mole of strong acid will have one halide that will react with the Na atom. Since there are two Na atoms in each of the molecule of Na2HPO4, this will need 2 halide atoms. 
5 0
3 years ago
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