Question

the cyclist has a mass of 50kg and is acceleratiing at 0.9m/s^2. What is the size of the unbalanced force F acting on the cyclist?

Answer 1

Answer:

45 N

Explanation:

The question can be solved by using Newton's second law:

F = ma

where

F is the net (unbalanced) force on the cyclist

m is the mass of the cyclist

a is his acceleration

In this problem:

m = 50 kg

$a=0.9 m/s^2$

Therefore, the unbalanced force is

$F=(50)(0.9)=45 N$