the cyclist has a mass of 50kg and is acceleratiing at 0.9m/s^2. What is the size of the unbalanced force F acting on the cyclis
1 answer:
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Answer:
Usually, zeroes are found to the right of a decimal point in significant numbers if you have something like (exaggerated example of course), which is when you have a number that is very very close to the integer before it, but isn't that integer.
Answer:
F=248.5W N
Explanation:
Newton's 2nd Law tells us that F=ma. We will use their averages always. The average acceleration the tennis ball experimented is, by definition:
Since we start counting at 0s and the ball departs from rest, this is just
So we can write:
Where in the last step we have just multiplied and divided by g, the acceleration of gravity. This allows us to introduce the weight of the ball W since W=gm, so we have:
Substituting our values:
Where the average force exerted has been written it terms of the tennis ball's weight W.
Answer:
Explanation:
x = Displacement in x direction = 5.34 m
t = Time taken to travel the displacement
y = Displacement in y direction = 0
u = Initial velocity of ball = 7.7 m/s
g = Acceleration due to gravity =
Displacement in x direction is given by
Displacement in y direction is given by
The angle at which the ball was thrown is .