All categories

2 years ago

⃗ has the magnitude 15 cm and it makes and angle 40° with positive X axis. Calculate the X and Y component of ⃗.

Physics

1 answer:

topjm [15]2 years ago

3 0

The X component of the vector is 11.5 while the Y component is 9.6.

<h3>What are the components of a vector?</h3>

We know that a vector must posses both magnitude and direction. Now the vector could be resolved into the vertical and the horizontal components of the mixture.

In resolving this vector;

X component = 15 cm cos 40 degrees = 11.5

Y component = 15 cm sin 40 degrees = 9.6

Thus the X component of the vector is 11.5 while the Y component is 9.6.

Learn more about vectors:brainly.com/question/13322477

#SPJ1

You might be interested in

A mailman performed 296 J of work lifting a box of 1.6 m. How much force did the mailman use?

Rus_ich [418]

185 newtons because (W=Fd so W/d=F)296/1.6=185

7 0

3 years ago

A hollow sphere of radius 0.200 m, with rotational inertia I = 0.0484 kg·m2 about a line through its center of mass, rolls witho

d1i1m1o1n [39]

Answer:

Part a)

$KE_r = 8 J$

Part b)

v = 3.64 m/s

Part c)

$KE_f = 12.7 J$

Part d)

$v = 2.9 m/s$

Explanation:

As we know that moment of inertia of hollow sphere is given as

$I = \frac{2}{3}mR^2$

here we know that

$I = 0.0484 kg m^2$

R = 0.200 m

now we have

$0.0484 = \frac{2}{3}m(0.200)^2$

$m = 1.815 kg$

now we know that total Kinetic energy is given as

$KE = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2$

$KE = \frac{1}{2}mv^2 + \frac{1}{2}I(\frac{v}{R})^2$

$20 = \frac{1}{2}(1.815)v^2 + \frac{1}{2}(0.0484)(\frac{v}{0.200})^2$

$20 = 1.5125 v^2$

$v = 3.64 m/s$

Part a)

Now initial rotational kinetic energy is given as

$KE_r = \frac{1}{2}I(\frac{v}{R})^2$

$KE_r = \frac{1}{2}(0.0484)(\frac{3.64}{0.200})^2$

$KE_r = 8 J$

Part b)

speed of the sphere is given as

v = 3.64 m/s

Part c)

By energy conservation of the rolling sphere we can say

$mgh = (KE_i) - KE_f$

$1.815(9.8)(0.900sin27.1) = 20- KE_f$

$7.30 = 20 - KE_f$

$KE_f = 12.7 J$

Part d)

Now we know that

$\frac{1}{2}mv^2 + \frac{1}{2}I(\frac{v}{r})^2 = 12.7$

$\frac{1}{2}(1.815) v^2 + \frac{1}{2}(0.0484)(\frac{v}{0.200})^2 = 12.7$

$1.5125 v^2 = 12.7$

$v = 2.9 m/s$

8 0

3 years ago

A 2000 kg car slams on the brakes and slows down at a rate of -10 m/s2. How much force are the brakes applying?

Gemiola [76]

Answer:

-20,000N

Explanation:

Force (N) = mass (kg) x acceleration (m/s²)

So,

Force = 2000 x -10

= -20,000N (Newtons)

5 0

3 years ago

2) A car is towed by a horizontal rope at a constant speed.<br> draw the free body diagram

Temka [501]

Answer:

Explanation:

8 0

3 years ago

Would u rather/ be in avengers or x-men

vlabodo [156]

X men those mutants are amazing

6 0

3 years ago