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just olya [345]
3 years ago
10

Which of the following statements is TRUE? The side of the Moon facing away from the Earth is in perpetual darkness. The Moon is

visible only at night. The Moon goes through a cycle of phases because it always has the same side facing the Earth. The Moon's distance from the Earth varies during its orbit. If you observed the Moon from North America and found that it was a full Moon, then someone in South America would see a new Moon.
Physics
1 answer:
Ivanshal [37]3 years ago
5 0

Answer:

The Moon's distance from the Earth varies during its orbit

Explanation:

The correct statement is ,The Moon's distance from the Earth varies during its orbit.

Important point regarding moon:

1 .Moon is a natural satellite of the earth.

2. Moon is the fifth largest satellite in solar system.

3.Second densest  satellite in solar system.

4.Moon rotates about earth.

5.Moon is an astronomical body .

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Two solenoids are equal in length and radius, and the cores of both are identical cylinders of iron. However, solenoid A has fou
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Answer:

\dfrac{L_A}{L_B}=16

Explanation:

\mu_0 = Vacuum permeability = 4\pi \times 10^{-7}\ H/m

n = Number of turns

A = Area

I = Current

Self inductance is given by

L=\mu_0n^2IA

Here, A has more turns so the self-inductance of A will be higher

For A

L_A=\mu_0n_A^2IA=\mu_0(4n_B)^2IA     [\because n_A=4n_B]

For B

L_B=\mu_0n_B^2IA

Dividing the above two equations we have

\dfrac{L_A}{L_B}=\dfrac{\mu_0(4n_B)^2IA}{\mu_0n_B^2IA}\\\Rightarrow \dfrac{L_A}{L_B}=16

\therefore \dfrac{L_A}{L_B}=16

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3 years ago
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17. A force of 150N is applied at an angle of 60°
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Answer:7,500J

Explanation:

Work done=force× distance

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3 years ago
Jen is conducting an experiment involving a device known as a pith-ball electroscope, shown below.
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Answer:

bring each tube close to the plastic ball and note any movement of the ball

Explanation:

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A 40.0 kg wheel, essentially a thin hoop with radius 0.810 m, is rotating at 438 rev/min. It must be brought to a stop in 21.0 s
garik1379 [7]

Answer:

(a) Workdone = -27601.9J

(b) Average required power = 1314.4W

Explanation:

Mass of hoop,m =40kg

Radius of hoop, r=0.810m

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Wfinal=0

t= 21.0s

Rotation inertia of the hoop around its central axis I= mr²

I= 40 ×0.810²

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The change in kinetic energy =K. E final - K. E initail

Change in K. E =1/2I(Wfinal² -Winitial²)

Change in K. E = 1/2 ×26.24[0-(438×2π/60)²]

Change in K. E= -27601.9J

(a) Change in Kinetic energy = Workdone

W= 27601.9J( since work is done on hook)

(b) average required power = W/t

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Answer:

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