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nlexa [21]
3 years ago
7

When are zeros significant when found to the trailing (to the right) of the decimal point?

Physics
1 answer:
Lelechka [254]3 years ago
7 0

Answer:

Usually, zeroes are found to the right of a decimal point in significant numbers if you have something like 7\frac{1}{100000000000000000000000000} (exaggerated example of course), which is when you have a number that is very very close to the integer before it, but isn't that integer.

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I can't understand
alexdok [17]

Answer:

turtle

Explanation:

6 0
3 years ago
Why are noise considerations important in optical fiber communications? 3. Describe the principle of "population inversion".
pochemuha

Answer and Explanation:

the electronic devices always have some noises present in the signal

there are some important considerations in optical fiber communications these are.

  • the noise which is contributed by transmitter are electronic random noise, low frequency noise
  • noise which is contributed by laser are relative intensity noise, mode partition noise, conversion of phase noise to amplitude noise.
  • noise contributed by photo detector are quantum shot noise, shot noise from dark current, avalanche multiplication noise.

PRINCIPLE OF POPULATION INVERSION :

The principle of population inversion is defined as for production of high percentage of simulated emission for a laser beam the number of atoms in higher state should be greater than lower energy state

7 0
4 years ago
A man can jog 10 miles in 90 minutes. What’s his speed in mph?
Yuki888 [10]

Answer:

hi there!

the correct answer to this question is: 6.67 mph

Explanation:

you convert minutes to hours

10 miles * 60 mins / 90 mins

7 0
3 years ago
Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving -1.72 m/s. What is the veloc
Nuetrik [128]

The velocity of B after elastic collision is 3.45m/s

This type of collision is an elastic collision and we can use a formula to solve this problem.

<h3>Elastic Collision</h3>

v_2 = \frac{2m_1u_1}{m_1+m_2} - \frac{m_1 - m_2}{m_1 + m_2}u_2

The data given are;

  • m1 = 281kg
  • u1 = 2.82m/s
  • m2 = 209kg
  • u2 = -1.72m/s
  • v1 = ?

Let's substitute the values into the equation.

v_1 = \frac{2*281*2.82}{281+209} -\frac{281-209}{281+209}(-1.72)\\v_1 = 3.45m/s

From the calculation above, the final velocity of the car B after elastic collision is 3.45m/s.

Learn more about elastic collision here;

brainly.com/question/7694106

4 0
2 years ago
A positive point charge Q is located at x=a and a negative point charge −Q is at x=−a. A positive charge q can be placed anywher
Scilla [17]

Answer:

\vec{F}_x = \frac{2KQqa}{(a^2 + y^2)^{3/2}} \^x

Explanation:

The Coulomb's Law gives the force by the charges:

\vec{F} = K\frac{q_1q_2}{r^2}\^r

Let us denote the positon of the charge q on the y-axis as 'y'.

The force between 'Q' and'q' is

F_1 = K\frac{Qq}{x^2 + y^2}\\F_1_x = F_1\cos(\theta)

where Θ is the angle between F_1 and x-axis.

F_1_x = K\frac{Qq}{x^2 + y^2}(\frac{x}{\sqrt{x^2 + y^2}}) = \frac{KQqa}{(a^2 + y^2)^{3/2}}

whereas

F_2_x = K\frac{-Qq}{a^2 + y^2}(-\frac{a}{\sqrt{a^2 + y^2}}) = \frac{KQqa}{(a^2 + y^2)^{3/2}}

Finally, the x-component of the net force is

\vec{F}_x = \frac{2KQqa}{(a^2 + y^2)^{3/2}} \^x

8 0
4 years ago
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