Answer:
The work done required on the coin during the displacement is 21.75 w.
Explanation:
Given that,
A coin slides over a friction-less plane i.e friction force = 0.
The co-ordinate of the given point is (1.40 m, 7.20 m).
The position vector of the given point is represented by 
.
The displacement of the coin is
The force has magnitude 4.50 N and its makes an angle 128° with positive x axis.
Then x component of the force = 4.50 cos128°
The y component of the force = 4.50 sin128°
Then the position vector of the force is
We know that,
work done is a scalar product of force and displacement.
=(-2.77×1.40+ 3.56×7.20) w
=21.75 w
The work done required on the coin during the displacement is 21.75 w.
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Answer:
Explanation:
Given
Weight of car 
mass of car 
velocity of car 
radius 
(a)Centripetal acceleration is given by
(b)Force that provide centripetal acceleration
(c)Friction force between car and tires is given by
where 
=coefficient of static friction
N=normal reaction
Centripetal force will balance the friction force
Answer:
t = 1.09 s.
Explanation:
This is a one-dimensional kinematics question, so the equations of kinematics will be sufficient to solve the question.
This quadratic equation can be solved using determinant.
Of course, we will choose the positive time.
Answer:
Explanation:
Cross multiply
cross multiply
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