All categories

3 years ago

Which force causes a soccer ball to take a curved path when it is kicked?

Physics

1 answer:

marysya [2.9K]3 years ago

6 0

Answer:

velocity

Explanation:

velocity is the only option that deals with change in direction, or best put by this website i read about physics; "Velocity measures motion starting in one place and heading toward another place."

You might be interested in

I’m designing a kitchen for a person in a wheel chair, which accommodation is least important? A. Provide turn around space for

Valentin [98]

The least important accommodation would be C.

7 0

3 years ago

Read 2 more answers

if the amplitude of sine curve is 4 and the frequency is 1 with no phase shift, what is the function that descirbes this curve?

Vlada [557]

Answer:

y = 4 Sin (2πt)

Explanation:

Amplitude, A = 4

frequency, f = 1

Wave function is given by

y = A sinωt

where, ω is angular frequency

ω = 2 π f = 2 π x 1 = 2π

So, the desired wave function

y = 4 Sin (2πt)

8 0

4 years ago

What happens to the mass and to the weight of the foam rubber when it is compressed?

Orlov [11]

Answer:

423523523523

Explanation:

52334W53WR53WRRWRW35423

4 0

2 years ago

Read 2 more answers

Which two of the following actions would

Ganezh [65]

Answer is d using a heavier string

5 0

3 years ago

If it has enough kinetic energy, a molecule at the surface of the Earth can "escape the Earth's gravitation", in the sense that

user100 [1]

Answer:

$K_E=mgr_E$

Explanation:

By conservation of energy, the sum of the kinetic and gravitational potential energies at the surface of the Earth must be equal than their sum at infinity, so we have:

$K_E+U_E=K_\infty+U_\infty$

$\frac{mv_E^2}{2}-\frac{GM_Em}{r_E}=\frac{mv_\infty^2}{2}-\frac{GM_Em}{r_\infty}$

Where $G=6.67\times10^{-11}Nm^2/kg^2$ is the gravitational constant, $M_E=5.97\times10^{24}kg$ and $r_E=6371000m$ are the mass and radius of the Earth, <em>m </em>is the mass of the particle, $v_E$ its velocity at the surface of the Earth (which would be its escape velocity) and $v_\infty$ and $r_\infty$ are the velocities and distance at infinity, which would be null and infinity respectively, so the right hand side of our equation is 0J, which leaves us with:

$\frac{GM_Em}{r_E}=\frac{mv_E^2}{2}=K_E$

Also, since the force the molecule experiments is the force of gravity (disregarding drag), we can write its weight in terms of Newton's Law of Gravitation:

$F=mg=\frac{GM_Em}{r_E^2}$

Which means that:

$\frac{GM_Em}{r_E}=mgr_E$

So finally putting all together we can write:

$K_E=\frac{GM_Em}{r_E}=mgr_E$

4 0

3 years ago